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koban [17]
1 year ago
11

For each order pair (x,y) , determine whether it is a solution to the inequality 4x-6y_< - 18

Mathematics
1 answer:
anyanavicka [17]1 year ago
7 0

Solution:

Given:

4x-6y\leq-18

To determine if an ordered pair is a solution, we substitute the x and y-values into the inequality and check if it is true.

Thus,

\begin{gathered} For\text{ the point }(-9,-2) \\ x=-9,y=-2 \\ 4x-6y\leq-18 \\ 4(-9)-6(-2)=-36+12=-24 \\ Since\text{ }-24

\begin{gathered} For\text{ the point }(0,3) \\ x=0,y=3 \\ 4x-6y\leq-18 \\ 4(0)-6(3)=0-18=-18 \\ Since\text{ }-18=-18,\text{ then }(0,3)\text{ is a solution} \end{gathered}

\begin{gathered} For\text{ the point }(5,-3) \\ x=5,y=-3 \\ 4x-6y\leq-18 \\ 4(5)-6(-3)=20+18=38 \\ Since\text{ }38>-18,\text{ then }(5,-3)\text{ is not a solution} \end{gathered}

\begin{gathered} For\text{ the point }(8,5) \\ x=8,y=5 \\ 4x-6y\leq-18 \\ 4(8)-6(5)=32-30=2 \\ Since\text{ }2>-18,\text{ then }(8,5)\text{ is not a solution} \end{gathered}

Therefore, the correct answers are selected as shown below;

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Answer:

(0,-5). y=mx+b or -5=0 × 0+b, or solving for b: b=-5-(0)(0). b=-5.

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Answer:

The function is defined when x > 0

Step-by-step explanation:

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We also know that functions with radicals are undefined when the value in the radicals are negative, because the root of a negative number is imaginary.  .  8x^{2} will always be positive, but 2x is negative when x < 0.

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