I just had this problem at rsm
the answer is 950 trees
Answer:
5.93 years
Step-by-step explanation:
The continuous compounding formula tells you the amount after t years will be ...
A = Pe^(rt) . . . . principal P compounded continuously at annual rate r for t years
7400 = 5500e^(0.05t)
ln(7400/5500) = 0.05t . . . . divide by 5500, take natural logs
t = 20×ln(74/55) ≈ 5.93
It will take about 5.93 years for $5500 to grow to $7400.
Answer:
q8h dosage = 112.5mg
Step-by-step explanation:
Given
Child Weight = 22.5 kg
Daily Intravenous Dosage = 40mg/kg
Type of Dose = q8h
Required
Calculate the q8h per dose
We start by calculating the total daily dosage in mg
This is calculated by multiplying the child weight by the intravenous dosage
Daily Dosage = 22.5kg * 40mg/kg
Daily Dosage = 900mg
This implies that the body weight requires 900 mg daily
Next is to calculate the q8h dosage
q8h means every 8 hours.
q8h dosage = 900mg/8
q8h dosage = 112.5mg
A= 3
b= 4
=3.14(a^2 + ab)
substitute the given a & b values in expression
=3.14((3)^2 + (3*4))
multiply inside parentheses
=3.14(9 + 12)
add inside parentheses
=3.14(21)
multiply
=65.94
ANSWER: 65.94
Hope this helps! :)
Answer: The required solution is
Step-by-step explanation: We are given to solve the following differential equation :
Let us consider that
be an auxiliary solution of equation (i).
Then, we have
Substituting these values in equation (i), we get
![m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.](https://tex.z-dn.net/?f=m%5E2e%5E%7Bmt%7D%2B10me%5E%7Bmt%7D%2B25e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%5E2%2B10y%2B25%29e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B10m%2B25%3D0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7De%5E%7Bmt%7D%5Cneq0%5D%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B2%5Ctimes%20m%5Ctimes5%2B5%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%2B5%29%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20m%3D-5%2C-5.)
So, the general solution of the given equation is
Differentiating with respect to t, we get
According to the given conditions, we have
and
Thus, the required solution is
