The side of a square is 3 and 5/2 inches

If mx=x+5/x-1 and n(x) = x – 3, which function has the same domain as (m*n)(x)

Ne4ueva [31]

Answer:c

Step-by-step explanation:

Given

$m\left ( x\right )=x+\frac{5}{x-1}$

and $n\left ( x\right )=x-3$

m of n is given by replacing x in $m\left ( x\right )$ by x-3

$m\left ( n\left ( x\right )\right )=x-3+\frac{5}{x-3-1}=x-3+\frac{5}{x-4}$

$m\left ( n\left ( x\right )\right )$ can take any value of x except x=4 because at x=4 function is not defined

and $h\left ( x\right )=\frac{11}{x-4}$ is also not defined for x=4 and can take any value of x

7 0

3 years ago

Emma earned a grade of 95% on her multiple choice history final that had a total of

Scrat [10]

Answer:

171

Step-by-step explanation:

180×95/100

180×95=17100

17100/100=171.

That is how I got my answer.

7 0

2 years ago

A heat pump cycle whose coefficient of performance is 2.5 delivers energy by heat transfer to a dwelling at a rate of 20 kW.

jasenka [17]

Answer:

Net power = 20kW

B.) $128

Step-by-step explanation:

Given that :

Coefficient of performance = 2.5

Rate = 20kW

The net power required to operate the heat pump :

Energy delivery rate / Coefficient of performance

= 20kW / 2.5

= 8kW

B.) Given that electricity cost equals $0.08 per kW

If pump operates for 200 hours

Total energy used in kWhr :

8kW * 200= 1600kW

Cost per kW = $0.08

1600 * 0.08 = $128

3 0

3 years ago

6,237.2 the 2 in the hundreds place is____the value of the 2 in the tenths place.

kotykmax [81]

1,000 times the value of the 2 in the tenths place.

6 0

3 years ago

Read 2 more answers

Two fair dice are tossed, and the up face on each die is recorded. Find the probability of observing each of the following event

astraxan [27]

Answer:

Probability of getting a die which 5 does not appear on each side is 5/6
probability of getting numbers of which the difference is 2 is 1/9
Probability of obtaining numbers that the sum is equal to or greater than 10 is 1/12

Step-by-step explanation:

When two dies are tossed, possible outcomes are (1,1) (1,2) ,(1,3) (1,4), (1,5) (1,6),(2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1)(3,2)(3,3)(3,4),(3,5)(3,6)(4,1) (4,2),(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

so the total sample space =36

From de possible outcome, probability of getting a die that five does not appear on either side is given by total outcome of not getting five from either side/sample space

=30/36 = 5/6

And also probability of getting the difference of numbers to be 2 are (3,1)(4,2) (5,3) (6,4) =4outcomes

the probability of getting a difference of 2 is given by outcome/sample space 4/36 = 1/9

probability of getting the summation of two numbers to be equal to or greater than ten are; Outcome/sample space.

the outcome are (4,6) (5,5) (5,6)(6,4)(6,5)and (6,6)= 6outcomes

=6/36 =1/12.

6 0

3 years ago