Simplify the equation 6/x-1-5x/4

gina has a box of red blue and green markers. The ratio of the number of red markers to the number blue markers is 5:2. The rati

sweet [91]

This can be solve by cancel of units

Snice red/ bkue = 5/2

And bkue/ green = 3/ 5

So red/ green = (red/ bkue) x( blue/ green)

Red/ green = (5/ 2) x (3/ 5)

Red / green = 3 /2

So the ratio of red is to green is 3: 2

3 0

3 years ago

Read 2 more answers

ronaldo delivers the papers at the rate of 6 papers in 24 minutes. how much longer would it take him to deliver 56 papers than 4

UkoKoshka [18]

We are given

Ronaldo delivers the papers at the rate of 6 papers in 24 minutes

so, number of papers =6 in time =24 minutes

so, firstly we can find rate

rate = ( number of papers)/( time taken)

$r=\frac{6}{24} =\frac{1}{4}$

now, we can find times

Time for 56 papers:

we are given

number of papers =56

rate is

$r=\frac{1}{4}$

now, we can find time

$t_1=\frac{56}{r}$

$t_1=\frac{56}{\frac{1}{4}}$

$t_1=224min$

Time for 41 papers:

we are given

number of papers =41

rate is

$r=\frac{1}{4}$

now, we can find time

$t_2=\frac{41}{r}$

$t_2=\frac{41}{\frac{1}{4}}$

$t_2=164min$

now, we can find time difference

$t=t_1-t_2$

so, we can plug values

$t=224-164$

$t=60 min$ ..............Answer

8 0

4 years ago

Read 2 more answers

Is the 161 rounded to the nearest 10 or to the nearest 100

kaheart [24]

Answer:

10

Step-by-step explanation:

so you can make it 200

5 0

3 years ago

What is an outlier? How does it effect data like mean, median, and mode?

pogonyaev

An outlier is a number much smaller or larger than the rest of the group of numbers. And outlier does not affect the median or the mode at all. It only affects the mean.

3 0

3 years ago

A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T

CaHeK987 [17]

Answer:

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :

Null hypothesis: $\mu \leq 75$

Alternative hypothesis: $\mu > 75$

A. One-Tailed

$z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189$

$p_v =P(z>2.189)=0.0143$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Data given and notation

We have the following data: 84 94 80 88 77 68 90 74 96 71

We can calculate the sample mean with the following formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X=82.2$ represent the sample mean

$\sigma=10.4$ represent the population standard deviation

$n=10$ sample size

$\mu_o =75$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :

Null hypothesis: $\mu \leq 75$

Alternative hypothesis: $\mu > 75$

A. One-Tailed

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189$

P-value

Since is a ONE-TAILED test the p value would given by:

$p_v =P(z>2.189)=0.0143$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

5 0

3 years ago