Answer:
h(-1) = 8
h(-2) = 11
h(-12) = 41
Step-by-step explanation:
h(x) = -3x + 5
h(-1) = -3(-1) + 5 = 3 + 5 = 8
h(-2) = -3(-2) + 5 = 6 + 5 = 11
h(-12) = -3(-12) + 5 = 36 + 5 = 41
Answer:
6.25 grams
Step-by-step explanation:
Since we need to find the number of half-lives in 26.3 years, we simply divide 26.3 yrs by 5.26 yrs which yields 5 half-lives. This means that in 26.3 yrs the 200 grams of cobalt-60 will undergo 5 half-lives.
To obtain the remaining amount we simplify the expression;
A = 200*(1-0.5)^(26.3/5.26)
= 200*(0.5)^(5)
= 6.25 grams.
Therefore, the amount of a 200 g sample of colbalt-60 that will remain after 26.3 years is 6.25 grams
If the cube width is 8^2= 64
Answer:
10.990 both in hundredth i believe.
Step-by-step explanation:
TOA
tan (20) = 4 / x
x = 4 / tan(20)
x = 10.990