Answer:
Find Radius using distance formula.
![radius = \sqrt{(8 -- 7)^2 +(7--1)^2} \\](https://tex.z-dn.net/?f=radius%20%3D%20%5Csqrt%7B%288%20--%207%29%5E2%20%2B%287--1%29%5E2%7D%20%5C%5C)
=![\sqrt{15^2 + 8^2} = \sqrt{225 + 64 } =\sqrt{289} = 17 units](https://tex.z-dn.net/?f=%5Csqrt%7B15%5E2%20%2B%208%5E2%7D%20%3D%20%5Csqrt%7B225%20%2B%2064%20%7D%20%20%3D%5Csqrt%7B289%7D%20%3D%2017%20units)
Since the point (-15, y) lies on the circle. The distance between (-7, -1) and
(-15, y ) will be 17 units.
So again using distance formula we will find y.
![radius = \sqrt{(-7 --15)^2 + (-1-y)^2} \\\\17 = \sqrt{8^2 + (y+1)^2}\\\\squaring \ both \ sides \\\\289 = 64 + (y+1)^2\\\\289-64=(y+1)^2\\\\225 = (y+1)^2\\\\taking \ squaring \ root\\\\15 = y+1\\\\y=14](https://tex.z-dn.net/?f=radius%20%3D%20%5Csqrt%7B%28-7%20--15%29%5E2%20%2B%20%28-1-y%29%5E2%7D%20%5C%5C%5C%5C17%20%3D%20%5Csqrt%7B8%5E2%20%2B%20%28y%2B1%29%5E2%7D%5C%5C%5C%5Csquaring%20%5C%20both%20%5C%20sides%20%5C%5C%5C%5C289%20%3D%2064%20%2B%20%28y%2B1%29%5E2%5C%5C%5C%5C289-64%3D%28y%2B1%29%5E2%5C%5C%5C%5C225%20%3D%20%28y%2B1%29%5E2%5C%5C%5C%5Ctaking%20%5C%20squaring%20%5C%20root%5C%5C%5C%5C15%20%3D%20y%2B1%5C%5C%5C%5Cy%3D14)
point (-15, 14)
7,4 is the new cordinate
all you have to do is add
[ 4+3, 3+1 ]
The perimeter is 72 and P=2(L+W), furthermore, L=2W so altogether...
2(L+W)=72 and using L=2W in this we have:
2(2W+W)=72
3W=36
W=12 and since L=2W
L=24
So the length is 24cm and the width is 12cm.
Answer:
Hey there!
We have an=a1(r^n-1), which is the formula for a geometric sequence.
The common ratio is 3, and 2 is the 1st term.
Thus, we have a1=2(3)^(n-1)
Hope this helps :)