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telo118 [61]
3 years ago
8

The formula v= u + at can be used to calculate Rearrange the formula to make u the subject.

Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

u = v - at

Step-by-step explanation:

v = u + at

v - at = u + at - at

v - at = u

u = v - at

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What is the mode of the data shown below?
aev [14]
C
there can be more than one mode. 20 and 30 have the same amount and are most frequent
3 0
2 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function f(x)=(x^{2},4x,z^{2}) and curve C is ellipse of equation

16x^{2} + 4y^{2} = 3

Theory: Stokes Theorem is given by:

I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx

Where, Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Also, f(x) = (F1,F2,F3)

\hat{N} = grad(g(x))

Using Stokes Theorem,

Surface is given by g(x) = 16x^{2} + 4y^{2} - 3

Therefore, tex]\hat{N} = grad(g(x))[/tex]

\hat{N} = grad(16x^{2} + 4y^{2} - 3)

\hat{N} = (32x,8y,0)

Now,  f(x)=(x^{2},4x,z^{2})

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

I= \int \int\limits {Curl f\cdot \hat{N} } \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0
3 years ago
Use this system of equations to answer the questions
Over [174]

Answer:

1. To eliminate x-term, multiply the second by -2

2. To eliminate y-term, multiply the second by 3

Step-by-step explanation:

4x - 9y = 7 (1)

-2x + 3y = 4 (2)

1. To eliminate x-term, multiply the second by -2

-2x + 3y = 4 (2) × 2

-4x + 6y = 8 (3)

4x - 9y = 7 (1)

Add (3) and (1)

6y - 9y = 8 + 7

-3y = 15

y = 15/-3

y = -5

4x - 9y = 7 (1)

4x - 9(-5) = 7

4x + 45 = 7

4x = 7 - 45

4x = -38

x = -38/4

x = -9.5

4x - 9y = 7 (1)

-2x + 3y = 4 (2)

2. To eliminate y-term, multiply the second by 3

-2x + 3y = 4 (2) × 3

-6x + 9y = 12 (3)

4x - 9y = 7 (1)

-6x + 4x = 12 + 7

-2x = 19

x = 19/-2

x = -9.5

4x - 9y = 7 (1)

4(-9.5) - 9y = 7

-38 - 9y = 7

-38 - 7 = 9y

-45 = 9y

y = -45/9

y = -5

6 0
2 years ago
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Kruka [31]

Answer:

The best answer would be C

Step-by-step explanation:

The square has two parallel lines and the rhombus has parallel lines as well. And when you turn the square, it looks like a rhombus. They are both parallelograms and quadrilaterals.

Hope this helps

7 0
3 years ago
Shaded area question PLS HELP ASAp
AfilCa [17]

Answer c I’m pretty sure

Step-by-step explanation:

3 0
3 years ago
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