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jeka94
3 years ago
15

Find the value of h(45) for the function below. h(x)=1/9(90 - x). A. 15 B. 5 C. -35 D. -315

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

Inverse Functions

One-to-one

Suppose f : A ⇥ B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c ⇤ A with

a ⌅= c, we are guaranteed that f(a) ⌅= f(c).

Example. f : R ⇥ R where f(x) = x2 is not one-to-one because 3 ⌅= 3

and yet f(3) = f(3) since f(3) and f(3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two dierent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ⇥ R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

66

Inverse Functions

One-to-one

Suppose f : A —* B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c e A with

a ~ c, we are guaranteed that f(a) $ f(c).

Example. f : IR —* JR where f(x) = x2 is not one-to-one because 3 ~ —3

and yet f(3) = f(—3) since f(3) and f(—3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(.x) in more than one point,

then f(z) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate — for example, (2,3) and

(4,3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two different objects in the domain to the same object

of the target.

If every horizontal line in JR2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : JR —, R where f(z) = z2. There is a

horizontal line that intersects this h in more than one point, so f is not

Step-by-step explanation:

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Function f is an exponential function. It predicts the value of a famous painting, in thousands of dollars, as a function of the
nalin [4]

Answer:

y=8 \cdot (\frac{5}{4})^x

f(x)=8 \cdot (\frac{5}{4})^x

or

f(x)=8 \cdot (1.25)^x

Step-by-step explanation:

We are going to see if the exponential curve is of the form:

y=a \cdot b^x, (b\neq 0).

If you are given the y-intercept, then a is easy to find.

It is just the y-coordinate of the y-intercept is your value for a.

(Why? The y-intercept happens when x=0. Replacing x with 0 gives y=a \cdot b^0=a \cdot 1=a. This says when x=0 \text{ that} y=a.)

So a=8.

So our function so far looks like this:

y=8 \cdot b^x

Now to find b we need another point. We have two more points. So we will find b using one of them and verify for our resulting equation works for the other.

Let's do this.

We are given (1,10) is a point on our curve.

So when x=1, y=10.

10=8 \cdot b^1

10=8 \cdot b

Divide both sides by 8:

\frac{10}{8}=b

Reduce the fraction:

\frac{5}{4}=b

So the equation if it works out for the other point given is:

y=8 \cdot (\frac{5}{4})^x

Let's try it.  So the last point given that we need to satisfy is (2,12.5).

This says when x=2, y=12.5.

Let's replace x with 2 and see what we get for y:

y=8 \cdot (\frac{5}{4})^2

y=8 \cdot \frac{25}{16}

y=\frac{8}{16} \cdot 25

y=\frac{1}{2} \cdot 25}

y=\frac{25}{2}

y=12.5

So we are good. We have found an equation satisfying all 3 points given.

The equation is y=8 \cdot (\frac{5}{4})^x.

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3 years ago
A recipe for 10 servings of raspberry sorbet calls for 2 cups of water, 1/1.2 cups of granulated sugar, and 4 cups of frozen ras
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3 0
3 years ago
Read 2 more answers
The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and
Delicious77 [7]

The width of rectangle is 2\frac{1}{4}\ cm and length is 5\frac{5}{12}\ cm

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = w+3\frac{1}{6}=w+\frac{19}{6}

Perimeter of rectangle = 15\frac{1}{3}=\frac{46}{3}\ cm

Perimeter of rectangle = 2(Length + Width)

2(w+\frac{19}{6}+w)=\frac{46}{3}\\2(2w+\frac{19}{6})=\frac{46}{3}\\4w+\frac{19}{3}=\frac{46}{3}

Subtracting \frac{19}{3} from both sides

4w+\frac{19}{3}-\frac{19}{3}=\frac{46}{3}-\frac{19}{3}\\4w=\frac{46-19}{3}\\4w=\frac{27}{3}\\4w=9

Dividing both sides by 4

\frac{4w}{4}=\frac{9}{4}\\w=\frac{9}{4}

Therefore,

Width of rectangle = w = \frac{9}{4}=2\frac{1}{4} cm

Length of rectangle = w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}=\frac{27+38}{12}=\frac{65}{12}=5\frac{5}{12}\ cm

The width of rectangle is 2\frac{1}{4}\ cm and length is 5\frac{5}{12}\ cm

Keywords: perimeter, addition

Learn more about addition at:

  • brainly.com/question/6270221
  • brainly.com/question/6275033

#LearnwithBrainly

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