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snow_tiger [21]
3 years ago
7

HELP PLEASEEEE!!! First correct answer gets brainliest! ​

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

It is a solution

Step-by-step explanation:

y = -4x - 8

Let x = -9 and y = 28

Substitute these values in

28 = -4(-9) -8

28 = 36 -8

28 =28

This is true so it is a solution

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Use the substitution method to solve the given system of equations. Write
ehidna [41]

Answer:

(-5/2 , 3/2)

Step-by-step explanation:

y=4+x

6(4+x) + 2x= 4

24 + 6x + 2x= 4

24 + 8x= 4

8x =4 - 24

8x=-20

x= -20/8= -5/2

y-(-5/2)=4

y+5/2= 4

multiply throughout by 2 to clear out fraction

2y + 5= 8

2y= 8-5

2y=3

y=3/2

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3 years ago
What is 20% of 60? Its a question for a exit ticket
tigry1 [53]

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12

Step-by-step explanation:

i looked it up

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What is the equation for m is between -2 and 5
Hatshy [7]
3 is my guess, tricky question tough?
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4 years ago
10. Use the discriminant to find the values of b for which the equation 4x2 + bx + 1 = 0 has one real solution.
il63 [147K]

Answer:

b = 4, or -4

Step-by-step explanation:

b^2 - 4*4*1 = 0

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8 0
2 years ago
Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
2 years ago
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