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snow_tiger [21]
3 years ago
7

HELP PLEASEEEE!!! First correct answer gets brainliest! ​

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

It is a solution

Step-by-step explanation:

y = -4x - 8

Let x = -9 and y = 28

Substitute these values in

28 = -4(-9) -8

28 = 36 -8

28 =28

This is true so it is a solution

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X^2 + 1/2x + = 2 + <br> Help please
Gennadij [26K]

Answer:

Step 2:

For Completing the square,

(\frac{1}{2} coefficient\ x)^{2} =(\frac{1}{2}\times \frac{1}{2})^{2}=\frac{1}{16}

Add half coefficient of x square on both the side we get

x^{2}+\dfrac{x}{2}+\frac{1}{16}=2+\frac{1}{16}

Step-by-step explanation:

Solve:

2x^{2}+x-4=0

2x^{2}+x=4

Solution:

Step 1:

Dividing both the side by two we get

x^{2}+\dfrac{x}{2}=2

Step 2:

For Completing the square,

(\frac{1}{2} coefficient\ x)^{2} =(\frac{1}{2}\times \frac{1}{2})^{2}=\frac{1}{16}

Add half coefficient of x square on both the side we get

x^{2}+\dfrac{x}{2}+\frac{1}{16}=2+\frac{1}{16}

Step 3:

We know (a +b)^{2} = a^{2}+2ab +b^{2}

(x+\frac{1}{4})^{2}=\frac{33}{16} \\ \\(x+\dfrac{1}{4})=\pm \sqrt{\dfrac{33}{16}} \\\\x=-\dfrac{1}{4}\pm \sqrt{\dfrac{33}{16}}

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To find the equation of line passing through points A (1, 3) and B (3, 7).

we know that, to derive the equation of a line we first need to calculate the slope of the line. Slope m of a line at points (x_{1} ,y_{1}) and (x_{2}, y_{2}) is given by - m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}.

Slope of the line at point A(1,3) and B(3,7)

m=\frac{7-3}{3-1}.

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