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RoseWind [281]
3 years ago
10

A triangle has sides 12cm, 9cm and 15cm. Is the triangle right-angled? Justify your answer

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

Yes this triangle is right angled and can be justified using the Pythagorean theorem. The theorem states that: a^{2} +b^{2} = c^{2}. Substitute using the given values:

(9^2)+(12^2)=15^2

81 + 144 = 255

255 = 255.

It satisfies the theorem therefore it is a right angle triangle.

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88 Is 20 percent of what number?
ValentinkaMS [17]

Answer:

  440

Step-by-step explanation:

You can write the problem statement in math terms as ...

  88 = 0.20 × (what number)

To solve this, divide by the coefficient of the variable, 0.20.

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The number you're looking for is 440.

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The table shows the number of shoppers at jacobs store over a period of five months
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7 0
3 years ago
the jurassic zoo charged $11 for each adult admission and $8 for each child. the total bill for the 195 people from a school tri
Otrada [13]

Children : 144

Adults : 51

Explanation

Step 1

Set the equations

let

x represents the number of children

y represents the number of adults

charge per child:8

charge per adult:11

total people:195

then

a)the total people is 195, so

x+y=195\rightarrow equation(1)

b) the total bill was $1713,so

total childrend +total adults=173

but,

total adults cost= rate*number of adults

total children cost= rate*number of childe

replacing

8x+11y=1713\rightarrow equation(2)

Step 2

solve the equations,

\begin{gathered} x+y=195\rightarrow equation(1) \\ 8x+11y=1713\rightarrow equation(2) \end{gathered}

a) isolate the x value from equation 81) and replace in eqaution (2)

\begin{gathered} x+y=195\rightarrow equation(1) \\ \text{subtract y in both sides} \\ x+y-y=195-y \\ x=195-y \end{gathered}

replace in equation (2)

\begin{gathered} 8x+11y=1713\rightarrow equation(2) \\ 8(195-y)+11y=1713 \\ 1560-8y+11y=1713 \\ 3y+1560=1713 \\ \text{subtract 1560 in both sides} \\ 3y+1560-1560=1713-1560 \\ 3y=153 \\ \text{divide bothsides by 3} \\ \frac{3y}{3}=\frac{153}{3} \\ y=51 \end{gathered}

therefore, the number of adults is 51

b) now, replace the y value into equation (1) to find x

\begin{gathered} x+y=195\rightarrow equation(1) \\ x+51=195 \\ \text{subtract 51 in both sides} \\ x+51-51=195-51 \\ x=144 \end{gathered}

so, the number of children is 144

I hope this helps you

4 0
2 years ago
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