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RoseWind [281]
3 years ago
10

A triangle has sides 12cm, 9cm and 15cm. Is the triangle right-angled? Justify your answer

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

Yes this triangle is right angled and can be justified using the Pythagorean theorem. The theorem states that: a^{2} +b^{2} = c^{2}. Substitute using the given values:

(9^2)+(12^2)=15^2

81 + 144 = 255

255 = 255.

It satisfies the theorem therefore it is a right angle triangle.

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Blake Ewasko's charge account uses the unpaid balance method to compute the finance
aev [14]

Answer:

$1,114.66

Step-by-step explanation:

Data provided in the question:

Monthly periodic rate = 2.15% = 0.0215

current Charges = $189.34

Payment made = $100.00

Finance charge = $21.54

Now,

Previous balance = Finance charges ÷ Rate

= $21.54 ÷ 0.0215

= $1001.86

Unpaid balance = Previous balance + Current charges - Payment

= $1001.86 + $189.34 - $100.00

= $1091.2

New balance = Unpaid balance × ( 1 + Rate )

= $1091.2 × ( 1 + 0.0215)

= $1,114.66

7 0
3 years ago
Determine the equation of the line that is perpendicular to the lines r(t)=(-2+3t,2t,3t)
Mnenie [13.5K]
<span>Vector Equation
(Line)</span>(x,y) = (x,y) + t(a,b);tERParametric Formx = x + t(a), y = y + t(b); tERr = (-4,-2) + t((-3,5);tERFind the vector equation of the line passing through A(-4,-2) & parallel to m = (-3,5)<span>Point: (2,5)
Create a direction vector: AB = (-1 - 2, 4 - 5) 
= (-3,-1) or (3,1)when -1 (or any scalar multiple) is divided out.
r = (2,5) + t(-3,-1);tER</span>Find the vector equation of the line passing through A(2,5) & B(-1,4)<span>x = 4 - 3t
y = -2 + 5t
;tER</span>Write the parametric equations of the line passing through the line passing through the point A(4,-2) & with a direction vector of m =(-3,5)<span>Create Vector Equation first:
AB = (2,8)
Point: (4,-3)
r = (4,-3) + (2,8); tER
x = 4 + 2t 
y = -3 + 8t
;tER</span>Write the parametric equations of the line through A(4,-3) & B(6,5)<span>Make parametric equations: 
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in -3
-3 = 5 + 4t 
(-8 - 5)/4 = t
-2 = t
For y sub in -8 
-8 = -2 + 3t
(-8 + 2)/3 = t
-2 = t
Parameter 't' is consistent so pt(-3,-8) is on the line.</span>Given the equation r = (5,-2) + t(4,3);tER, is (-3,-8) on the line?<span>Make parametric equations: 
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in 1
-1 = 5 + 4t 
(-1 - 5)/4 = t
-1 = t
For y sub in -7 
-7 = -2 + 3t
(-7 + 2)/3 = t
-5/3 = t
Parameter 't' is inconsistent so pt(1,-7) is not on the line.</span>Given the equation r = (5,-2) + t(4,3);tER, is (1,-7) on the line?<span>Use parametric equations when generating points: 
x = 5 + 4t
y = -2 + 3t ;tER
X-int:
sub in y = 0
0 = -2 + 3t
solve for t
2/3 = t (this is the parameter that will generate the x-int) 
Sub t = 2/3 into x = 5 + 4t 
x = 5 + 4(2/3)
x = 5 + (8/3)
x = 15/3 + (8/3) 
x = 23/3
The x-int is (23/3, 0)</span>What is the x-int of the line r = (5,-2) + t(4,3); tER?Note: if they define the same line: 1) Are their direction vectors scalar multiples? 2) Check the point of one equation in the other equation (LS = RS if point is subbed in)What are the two requirements for 2 lines to define the same line?
3 0
4 years ago
Pls help w explanation!!
Rama09 [41]

Answer:

A is the Answer

Step-by-step explanation:

Since the population is being split up into 2 divisions out of 5,000.

This means District X and Y must add up 5000.

x + y = 5000

District X and Y must differ no more than 500 people.

So this means that X and Y total people difference cannot be over 500 people. So the equation for this is

x - y \leqslant 500

A shows this so A is the answer.

8 0
3 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
3 years ago
Which of the following is a solution to this inequality? y&gt;1/2x+2
Travka [436]

I need help with this asw

5 0
3 years ago
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