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Leokris [45]
3 years ago
11

-9 a que conjunto pertenece -4/4 a que conjunto pertenece -5.124 a que conjunto pertenece rapidoo pls

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

-9 al conjunto de los números enteros.

-4/4 pertenece a los enteros.

-5.124 pertenece al conjunto de los racionales

Step-by-step explanation:

En esta pregunta, básicamente lo que debes hacer es clasificar cada uno de los números de acuerdo al conjunto numérico. Como podrás ver en la foto 1, tienes una representación gráfica de los conjuntos numéricos existentes.

Los números naturales (N), comprenden desde el 1 hasta el infinito.

Los números enteros (Z) comprenden los negativos, el cero y todos los naturales.

Finalmente los números racionales (Q) comprenden los números enteros, los naturales y también fracciones y números decimales.

De acuerdo a estas definiciones y la foto, podemos observar que todos los números dados acá pertenecen al conjunto general de los racionales (Q), pero veamos ahora específicamente a cual:

El número -9 (o el 9) si es negativo, pertenece a los enteros; si es positivo sería entero y natural.

El número -4/4 es una fracción, que al ser dividida da como resultado el número -1, y este pertenece a los enteros.

El número -5.124 (o 5.124) es un número decimal finito, por lo que proviene de una fracción, asi que pertenece a los números racionales.

Espero que esto te ayude.

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Answer: tea = 15 rupees  per kg

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Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

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t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

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  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

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