Answer:
The approximate difference in time is 2 years.
Step-by-step explanation:
The equation for Calvin's account is

To solve for c, we first divide both sides by 400. This gives us:

Using logarithms to solve this, we have

Dividing both sides by 12, we get c = 9.9998 or around 10 years.
The equation for Makayla's account is

Dividing both sides by 300, we get

Using logarithms to solve this, we have

Dividing both sides by 4, we get
m = 11.9999 or about 12.
This means Makayla had her money in the account 12-10 = 2 years longer than Calvin.