Answer:
what is the question please explain
Answer:
4
Step-by-step explanation:
Each walk-in is $5, so 20 divided by 5 is 4. 4 classes.
We start with
![2 x^{2} -20x-53](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20-20x-53)
and wish to write it as
![a(x+d) ^{2} +e](https://tex.z-dn.net/?f=a%28x%2Bd%29%20%5E%7B2%7D%20%2Be)
First, pull 2 out from the first two terms:
![2( x^{2} -10x)-53](https://tex.z-dn.net/?f=2%28%20x%5E%7B2%7D%20-10x%29-53)
Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have
![x^{2} -10x](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-10x)
and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square:
![x^{2} -10x+25=(x-5) ^{2}](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-10x%2B25%3D%28x-5%29%20%5E%7B2%7D%20)
The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have
![2( x-5) ^{2}-53](https://tex.z-dn.net/?f=2%28%20x-5%29%20%5E%7B2%7D-53%20)
and when we multiply that out it does not give us what we started with. It gives us
![2 x^{2} -20x+50-53=2 x^{2} -20x-3](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20-20x%2B50-53%3D2%20x%5E%7B2%7D%20-20x-3)
So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.
We do this as follows:
![2(x-5) ^{2}-53-50](https://tex.z-dn.net/?f=2%28x-5%29%20%5E%7B2%7D-53-50%20)
which gives us the final expression we seek:
![2(x-5) ^{2}-103](https://tex.z-dn.net/?f=2%28x-5%29%20%5E%7B2%7D-103%20)
If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e = -103
We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106
The base is the greatest surface area