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iris [78.8K]
2 years ago
7

Please help me with this question. will give brainliest I need this by today pleaseeeeeee its an assignment

Mathematics
2 answers:
coldgirl [10]2 years ago
6 0

Answer:

i would say 7

Step-by-step explanation:

Ivahew [28]2 years ago
6 0
I think it’s 7 also try it
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Jack is purchasing a stock that pays an annual dividend of $3.42 per share. If he purchases 400 shares for $53.18 per share, wha
sergij07 [2.7K]

Answer:

1368 dollars.

Step-by-step explanation:

given that Jack s purchasing a stock that pays an annual dividend of $3.42 per share

No of shares Jack purchased = 400

Price per share = 53.18$

Amount invested by Jack in shares = 400*53.18 =21272 dollars

Annual dividend = 3.42 per share

Total dividend = 400*3.42 = 1368

Annual income from dividends = 1368 $

7 0
4 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\
A_x=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =60
\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\
-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\
A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =120
\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]
\\\\\\
A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\
-------------------------------\\\\
\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
4 years ago
Cameron has 2 video game holder stands each can hold 2 rows of 20 games write and evaluate a numerical expression to find the to
Aleksandr [31]

Answer:

so this would be the equation

2(2*10)=v

So the number on the outside is the number of stands, the second 2 is for the two rows, and the 10 is the games. I did this because its two rows and combined they make 20 games. It took me a little to figure that out.

This shows the number of games total in both holders.


5 0
3 years ago
Can someone please help me
Mashutka [201]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Functions.

Let's first find the g(-1),

so we get as

3(-1)^2 +5(-1)-6

=> 3 -5-6

=> -8

now since g(-1) =-8

let's find f(g(-1)) that is f(-8)

f(-8) = 4(-8) + 14

=> f(g(-1)) = -32+14

=> f(g(-1)) = -18

-18 is the answer.

8 0
3 years ago
What is the gcf for 45 51 and 63
Marina86 [1]
Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 45, \  51\ and\\ 63\ can\ be\ divided\\\\
45:3\\
15:3\\
5:5\\\\
51:3\\
17:17\\\\63:3\\21:3\\7:7\\\\GCF=3\\\\Greatest\ common\ factor\ of\ 45,\ 63\ and\ 51\ is\ equal\ to\ 3.

7 0
3 years ago
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