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abruzzese [7]
3 years ago
12

What reasonable estimate of 288

Mathematics
1 answer:
erastova [34]3 years ago
4 0
Eight because you estimate to 88 it will become 300 so I think eight
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I’m stuck on this question if someone could help me I would highly appreciate:)
FinnZ [79.3K]
It’s the same so 36.6 because if they are vertical angles both sides are congruent
4 0
3 years ago
the perimeter of an equilateral triangle is 63 inches. if the length of each side is (4x-3), find the value of x
Ber [7]
Use the equation 4x-3=63
4 0
3 years ago
Solvethe equation 3(x-5)/2=2(x+5)/3
Nataliya [291]
3(x−5)/2=2(x+5)/3

Cross-multiply.

(3(x−5))/2=(2(x+5))/3

3(x−5)*(3)=2(x+5)*(2)

9x−45=4x+20

Subtract 4x from both sides.

9x−45−4x=4x+20−4x


5x−45=20

Add 45 to both sides.

5x−45+45=20+45

5x=65

Divide both sides by 5.

5x/5=65/5

x=13

6 0
4 years ago
Read 2 more answers
HELP PLEAAAAAAAAAAASE
dalvyx [7]
The answer is option B.
Because it can't be chocolate. 
4 0
3 years ago
(2³)² solve this problem
max2010maxim [7]

Answer:

(2^3)^2 = 64

Step-by-step explanation:

Option 1:

Using the following rule:

(a^n)^m = a^{nm}

Put in our expression,

a = 2

n = 3

m = 2

(a^n)^m = a^{nm}

(2^3)^2 = 2^{3*2}=2^6=64

Option 2:

Using the following rule:

a^n * a^m = a^{n+m}

Since our expression is the same as multiplying 2³ with itself, we can write it as a multiplication.

(2^3)^2 = 2^3 * 2^3

If we compare this with a^n * a^m, we can see that

a = 2

n = 3

m = 3 (in this case, n and m are equal)

a^n*a^m = a^{n+m}

2^3*2^3 = 2^{3+3} = 2^6 = 64

Answer: (2^3)^2 = 64

7 0
4 years ago
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