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2 years ago

PLSSSS HELP MEEE WITH THISSSS

Mathematics

1 answer:

VashaNatasha [74]2 years ago

7 0

Answer:

x=-6 y=-26

Step-by-step explanation:

in the first is -4 every time, in the second is -20 every time

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What is the solution of the following system?

erica [24]

Answer:

The answer to your question is: both lines are the same.

Step-by-step explanation:

3x + 3y = 10

-9x -9y = -30

Elimination method

9x + 9x = 30

-9x - 9y = -30

0 0 0

8 0

2 years ago

Find the volume of a cube that has a side length of: 6x²y5

777dan777 [17]

Answer:

Are this form 1 question

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2 years ago

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The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

2 years ago

4x-5y=15 can someone plz explain this

AVprozaik [17]

Well if you are solving for y
the answer is

Y= 4/5x- 3

if you are solving for x
the answer is
X=5/4y + 15/4

*look at the image for the work*

7 0

3 years ago

WHO DOESN'T LOVE MAX POINTS. MAX POINT QUESTION PLS ANSWER THIS TRIGONOMETRY QUESTION

mezya [45]

Answer:

Solution given:

opposite:9

adjacent: 12

$\theta=?$

Relationship between opposite and adjacent is given by tan angle

$Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}$

$Tan \theta=\frac{3}{4}$

$\theta=Tan^{-1}\frac{3}{4}$

$\bold{\theta=36.8°}$

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

$\theta=62°$

Relationship between height and hypotenuse is given by Sin angle

Sin 62°= $\frac{opposite}{hypotenuse}=\frac{b}{11}$

doing crisscrossed multiplication

b=Sin 62°*11

:.b=9.71 cm

a) At 9.71 cm height does the ladder touch the building.

again

Relationship between base and hypotenuse is given by Cos angle

:.Cos 62°= $\frac{base}{hypotenuse}=\frac{a}{11}$

doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is 5.16cm.

4 0

2 years ago