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seropon [69]
2 years ago
5

My last question someone help pls

Mathematics
1 answer:
lara [203]2 years ago
7 0

Answer:

3

Step-by-step explanation:

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HELPPPP PLEASEE. IT IS DUE IN 20 MIN. THANK YOU SO MUCH! :)
12345 [234]

Answer:

A.) 65x + 35X + 50 = 250

65x = cost of concrete per cubic yard, x is yd³

35X = cost of pouring/finishing concrete per cubic yard, X is yd³

50 = delivery cost

250 = the money you have

B.) 400 + 15n = 505

15n = amount of money you deposite per week, n is # of week

400 = some money in account after n week passed

505 = initial money in bank

C.) 1.1X - 10 = 55

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3 0
3 years ago
How can you tell whether a positive or negative association exists
stira [4]

Answer:

You can tell whether or not something is positive or negative by looking at the specific number for example if you look at this number -5 you know its a negative number because it has a - sign.Although when its positive it does not have any kind of format of signs according to my calculations.

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6 0
3 years ago
Please give me the correct answer ​
Ronch [10]

Answer:

I believe it's the last one.

8 0
3 years ago
Read 2 more answers
15 points
melisa1 [442]
Clockwise 270 degrees is the answer
5 0
3 years ago
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Researchers studying the acquisition of pronunciation often compare measurements made on the recorded speech of adults and child
dolphi86 [110]

Answer:

(A) The additional information that is needed to confirm about the conditions for this test have been met is ‘Population is approximately normal.

(B) The test statistic = 1.9965

(C1) P-value = 0.0556

(C2) There is no significant difference between mean VOT for children and adults.

D1) It is possible to make type II error.

(D2) There should be a difference in the VOT of adults and children.

Step-by-step explanation:

Let na be the number of adults = 20

xa mean VOT for adults = 88.17

sa standard deviatiation of VOT for adults = 24.74

Let nc be the number of children = 10

xc mean VOT for children =60.67

sc standard deviatiation of VOT for children = 39.89

(A) From the information the population variances are unknown and the two sample are assumed to be independent and the sample the sample size are smaller that is (n<30).

This indicates that the additional information that is required for the conditions of the test to be satisfied is 'distribution of the population'. the addition assumption to be made is, that the population distribution is normal.

(b) Calculating the test statistics using the formula;

t = (xa -xc)/SE - d

where SE = standard deviation , d= hypothesized difference = 0

But SE = √sa²/na +sc²/nc

           = √24.74 ²/20 + 39.89²/10

           = √189.72559

           = 13.774

Substituting into test statistics equation, we have

t = (xa -xc)/SE - d

  = (88.17 - 60.67/13.774

  = 1.9965

Therefore the test statistic is 1.9965

(c) Calculating the p-value, we have;

Degree of freedom = na + nc -2

                                 = 10+ 20 -2

                                 = 28

The p-value for t=1.9965 at 28 degrees of freedom and 0.05 level of significance is 0.0556.

The p-value 0.0556 is greater than given level of significance 0.05 hence we fail to reject the null hypothesis and conclude that there is no significant difference between mean VOT for children and adults.

(D1) From the information in part (C) the null hypothesis is not rejected.

Since the null hypothesis is not rejected, there might be a chance that not rejecting null hypothesis would be wrong. In this type of situation the error that can occur would be type II error.

(D2) The type of error describe in the context of this study is obtained by the concept of the type II error which tells that the null hypothesis is not rejected when it is actually false.

7 0
3 years ago
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