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4 years ago

5

9>xchoose all the answer that applyx=2x=5x=9

2 answers:

Gre4nikov [31]4 years ago

8 0

Answer:

X = 9

I could not find any of the others close to it,, sorry if I’m wrong

Step-by-step explanation:

Minchanka [31]4 years ago

7 0

X=9
That's the only thing I could find

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The average (arithmetic mean) of y numbers is x. if 30 is added to the set of numbers, then the average will be x - 5. what is t

Anastasy [175]

Given,

AM of y numbers = x.

Let the sum of y numbers be s.

AM of y numbers = x

$\frac{s}{y} = x$

$s = y*x$

Given, when 30 is added to the y numbers, the AM becomes x - 5.

$\frac{s + 30}{y + 1} = x - 5$

$\frac{y*x + 30}{y +1} = x - 5
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$y*x + 30 = (x -5)( y +1)$

$y*x + 30 = y*x + x - 5y -5$

$5y = x - 5 -30 = x - 35
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$y = \frac{x -35}{5}$

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4 years ago

What is the slope of the line? 7x+2y=57x+2y=5

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3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

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