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sdas [7]
3 years ago
12

Solve the inequality for x. Show each step of the solution. 10x>8(3x-2)-12

Mathematics
1 answer:
Anettt [7]3 years ago
8 0

Answer:

x < 2

Step-by-step explanation:

Given

10x > 8(3x - 2) - 12 ← distribute parenthesis on right side

10x > 24x - 16 - 12, that is

10x > 24x - 28 ( subtract 24x from both sides )

- 14x > - 28

Divide both sides by - 14, reversing the inequality symbol as a result of dividing by a negative quantity.

x < 2

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Andre45 [30]

Answer:

  7/6

Step-by-step explanation:

You have correctly graphed the line, so you know that the rate of change is ...

  ∆d/∆t = 7/6

d changes by 7/6 units for each unit change in t.

6 0
3 years ago
Explain: how would you model 5 x 2/3
ELEN [110]
Well as you can see 5 x 2/3= 3 1/3 there is 7 steps to figure it out

1. set up the problem
5 x 2/3

2. put a 1 on 5 to make it a fraction
5/1 x 2/3

3. multiply and divide
(5 x 2) / (1/3)

4. find out the answer
10/3

5. turn the answer into a mixed fraction
10 divided by 3= 3.1 3 stays the same you don't need to say 1

6. it equals
3 1/3

7. so the answer is
3 1/3

8 0
3 years ago
Read 2 more answers
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Tju [1.3M]

See the attached picture:

7 0
3 years ago
Write an equation of the parabola in vertex form.
Katena32 [7]

Answer:

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. ... When written in "vertex form": • (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.

6 0
3 years ago
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Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
Read 2 more answers
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