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3 years ago

Question:

Mathematics

1 answer:

katrin2010 [14]3 years ago

5 0

So this u I d asome and super cool idk what to say lol hahah

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Components of a certain type are shipped to a supplier in batches of ten. Suppose that 50% of all such batches contain no defect

ad-work [718]

Answer:

a) P (0 defective component) = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

b) P( 0 ) = 0

p ( 1 ) = 1

p ( 2 ) = 0.33

Step-by-step explanation:

p( no defective ) = 0.5

p( 1 is defective ) = 0.35

p( 2 is defective ) = 0.15

Given that 2 components are selected at random

a) Given that neither component is defective

Probability of 0 defective component = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

b) Given that one of the two tested component is defective

P( 0 defective ) = 0

P( 1 defective ) = P ( $\frac{x=1}{x\geq 1}$ ) = p( x = 1 ) / 1 - P ( x = 0 )

= ( 0.5 )^1 ( 0.5 )^0 / 1 - ( 0.5)^0 (0.5)^1

= 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 = 1

p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )

= ( 0.5 )^2 ( 0.5 )^0 / 1 - ( 0.5)^0 (0.5)^2

= 0.25 / 0.75 = 0.33

5 0

2 years ago

What is the range of the following relation? Oxso all real numbers

Vesnalui [34]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve Diego's equation: x + 35 =180 x =

Irina18 [472]

Answer:

x=145

Step-by-step explanation:

simply subtract 35 from both sides, so you can isolate the variable. once done, you will get that x=145

3 0

3 years ago

Read 2 more answers

20 points and brainliest I’m in quiz in need it asap Number 4

iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number $a+ib$ is the number $re^{i\theta}$ where $r = \sqrt{a^2+b^2}$ is called the modulus and $\theta = tan^-^1 (\frac ba)$ is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

$r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4$

now we can write the two numbers as

$z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}$

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

$Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}$

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

$(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4$

Now, in the last step I've used the fact that $e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z$ , or in other words, the complex exponential is periodic with $2\pi$ as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0

2 years ago

Complete the table for the given rule rule: y= x/2 X Y 8 __ 14 __ __ 3

Oxana [17]

Answer:

X Y

8 4

14 7

6 3

Step-by-step explanation:

y = x/2

x = 2y

5 0

3 years ago