Number of compounding periods is
n=12months×3years=36
I assume that
The total interest=
monthly payment×number of compounding periods - the amount of the present value of an annuity ordinary
I=x×n-pv
Let monthly payment be X
I =Total interest is 1505.82
The present value of an annuity ordinary is
Pv=X [(1-(1+0.09/12)^(-36))÷(0.09/12)]
now plug those in the formula of the total interest above
I=x×n-pv
1505.72=36X-X [(1-(1+0.09/12)^(-36))÷(0.09/12)]
Solve for X using Google calculator to get the monthly payment which is
X=330.72
Check your answer using the interest formula
36×330.72−330.72×((1−(1+0.09
÷12)^(−12×3))÷(0.09÷12))
=1,505.83
Answer:
1) C = 3
2) B = 5
3) C = 8
Step-by-step explanation:
Question 1)
We have:
Distribute:
Distribute:
Combine like terms:
Therefore, C = 3.
Question 2)
We have:
Distribute:
Distribute:
Combine like terms:
Therefore, B = 5.
Question 3)
We have:
Distribute:
Distribute:
Combine like terms:
So, C = 8.
Answer: clearly the answer is B hope this helps
Step-by-step explanation:
Answer:
option c) x₁₁ + x₁₂ = 8000
Step-by-step explanation:
Given:
xij = gallons of component i used in gasoline j
gallons of component 1 available = 8,000
demand gasoline types 1 = 11,000
demand gasoline types 2 = 14,000
Here, we have only component 1 available i.e i = 1 only
( therefore, all the options containing i = 2 gets eliminated )
thus,
component 1 will fulfill the demand of gasoline types 1 and 2 i.e j = 1 and 2
hence,
the equation satisfying the above conditions comes out as:
x₁₁ + x₁₂ = 8000
that means gallons of component 1 used in gasoline 1 and 2 and the total equals to the gallons of component 1 available i.e 8000
Answer:
Hi there
Your answer is
10 Bunches
Step-by-step explanation:
4 bunches= 8$
/8 for how many bunches per 1$
.5bunches= 1$
*20
10bunches=20$
