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3 years ago

VERY URGENT PLEASE HELP!!!!!!!

Mathematics

2 answers:

tigry1 [53]3 years ago

6 0

Answer:

H=3

Step-by-step explanation:

Fittoniya [83]3 years ago

3 0

Answer:

multiply 8 by 5 then round :D

Step-by-step explanation:

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How do I solve this equation for x?

lara31 [8.8K]

Answer:

The answer is x = -32

Step-by-step explanation:

In order to find the value of x, e must first distribute the 6 into the parenthesis.

6(x - 7) = 8x + 22

6x - 42 = 8x + 22

Now we will add/subtract values so that all x values are on the right and all number values are on the left.

6x - 42 = 8x + 22

-42 = 2x + 22

-64 = 2x

Now to get the final answer, divide both sides by 2.

-32 = x

5 0

3 years ago

A. 5/18 B. 4/9 C. 1/2 D. 5/9

schepotkina [342]

$|\Omega|=9\cdot8=72\\ |A \cap B|=5\cdot4=20\\\\ P(A \cap B)=\dfrac{20}{72}=\dfrac{5}{18}\Rightarrow \text{A}$

5 0

3 years ago

Solve this system of equations using the substitution method y = 2x + 17 y = 6x - 3

guapka [62]

Step-by-step explanation:

well, as you can witness both of the equations are equal to y, so you're free to reckon that they are equal as well

$6x - 3 = 2x + 17 = = = > \\ 4x = 20 = = = > x = 5 \: and \: \\ y = 6(5) - 3= = = > y = 27$

5 0

2 years ago

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$

6 0

3 years ago

Help me pleaseeee !!

ra1l [238]

Answer:

For x it would be 50 m2

Step-by-step explanation:

8 0

3 years ago