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Natalija [7]
3 years ago
9

Solve the system of linear equations by substitution! SHOW WORK PLEASE

Mathematics
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

x=2, y=6

Step-by-step explanation:

y=10-2x

x=y-4

substitute x

y=10-2(y-4)

y=10-2y+8

Add 2y to each side

3y=10+8=18

y=6

x=y-4

x=6-4=2

x=2

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the figure shown is a rectangle with a semicircle on each end. what is the area of the figure? use 3.14 for <img src="https://te
nirvana33 [79]

Answer:

\boxed{a.\:\:\:76.3\:in^2}

Step-by-step explanation:

The figure is made up of a rectangle and two semicircles.


We find the area of the rectangle using the formula;

Area = l\times w


\Rightarrow Area = 8\times 6


\Rightarrow Area = 48\:in^2.


We find the area of one of the semicircles and multiply by 2;


The area of the semicircles

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We substitute \pi =3.14 and r=3\:in to obtain;


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The area of the figure is

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To the nearest tenth we have;

=76.3\:in^2

The correct answer is A





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Since the numerator and denominator of have a common base, this expression can be rewritten as 2(3x−y). In the question, it states that 3x−y=12, so one can substitute 12 for the exponent, 3x−y, which means that

8x2y=212

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