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artcher [175]
3 years ago
11

The perimeter of a rectangle is 94 yards. The width is 23yards less than the length. Find the length and the

Mathematics
2 answers:
I am Lyosha [343]3 years ago
4 0
Length = 35 Width = 12

Perimeter = 2L+2W
Length = x
Width = x-23

94=2(x)+2(x-23)
94=2x+2x-46
94=4x-46
94+46
140=4x
140/4 4x/4
35=x (length)
35-23=12 (width)
kotykmax [81]3 years ago
3 0

Answer:

The length = 35 ; The width = 12

Step-by-step explanation:

Perimeter = 2L + 2W

Length = x

Width =  x - 23

 

94 = 2(x)  + 2(x - 23)

94 = 2x + 2x - 46

94 = 4x - 46

94 + 46 = 4x

140 = 4x

140/4 = x

35 = x           The length = 35; The width = (35 - 23) =  12

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Step-by-step explanation:

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7 0
1 year ago
Question 2
prisoha [69]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Calculating the area of the outer rectangle:</u>

Given

  • The length outer rectangle = l = 3x - 1
  • The width of outer rectangle = w = 5x + 2

Thus,

The area of the outer rectangle:

A = wl

    = (5x + 2) (3x - 1)

    =5x\cdot \:3x+5x\left(-1\right)+2\cdot \:3x+2\left(-1\right)

     =5\cdot \:3xx-5\cdot \:1\cdot \:x+2\cdot \:3x-2\cdot \:1

      =15x^2+x-2

<u>Calculating the area of the inner rectangle:</u>

Given

  • The length inner rectangle = l = x + 7
  • The width of inner rectangle = w = x

Thus,

The area of the outer rectangle:

A = wl

   = x(x+7)

   = x² + 7

<u>Calculating the area of the shaded region:</u>

As

The area of the outer rectangle = 15x² + x - 2

The area of the inner rectangle = x² + 7

  • The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.

Thus,

shaded region Area = Outer Rectangle Area - Inner Rectangle Area

                                  = 15x² + x - 2 - (x² + 7)

                                   =  15x² + x - 2 - x² - 7

                                   = 14x² + x - 9

Therefore, the Area of the shaded region is: 14x² + x - 9

4 0
3 years ago
A right △ABC is inscribed in circle k(O, r). Find the radius of this circle if:
natta225 [31]

We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

\text{sin}(30^{\circ})=\frac{AC}{AB}

\text{sin}(30^{\circ})=\frac{18}{AB}

AB=\frac{18}{\text{sin}(30^{\circ})}

AB=\frac{18}{0.5}

AB=36

Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is \frac{36}{2}=18.

Therefore, the radius of given circle would be 18 cm.

8 0
4 years ago
What is the probability that an offspring will have a homozygous dominant genotype?
Anton [14]

Answer:

The probability is 1/2% or 50%

Step-by-step explanation:

3 0
3 years ago
3 connecting lines are shown. Line D F is horizontal. Line D E is about half the length of line D F. Line F E is about one-third
mars1129 [50]

The inequality that explains why the three segments cannot be used to construct a triangle is ED + EF < DF

<h3>Inequalities </h3>

From the question, we are to determine which of the given inequalities explains why the three segments cannot be used to construct a triangle

From the given information,

Line DE is about half the length of line DF

That is,

ED = 1/2 DF

Also,

Line FE is about one-third of the length of line DF

That is,

EF = 1/3 DF

Then, we can write that

ED + EF = 1/2DF + 1/3DF

ED + EF = 5/6 DF

Since,

5/6 DF < DF

Then,

ED + EF < DF

Hence, the inequality that explains why the three segments cannot be used to construct a triangle is ED + EF < DF

Learn more on Inequalities here: brainly.com/question/1447311

#SPJ1

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