Given: In ΔDEF and ΔDGF, Side DF is common.
To prove congruent of the triangle, we must require the minimum three conditions; like two sides and one angle of one triangle should be equal to the other triangle. OR Three sides of one triangle should be equal to the other triangle. OR Two angles and one side of one triangle should be equal to the other triangle. etc.
As per given question, to prove congruent of given triangles by SAS property then we should have given two sides and one angle of one triangle should be equal to the other triangle as additional information.
Since, In ΔDEF and ΔDGF, Side DF is common. So, we should require only one side and one angle that should be equal to another triangle.
Answer: We need a problem but the answer is
Step-by-step explanation: u can use this if it helps
https://divisible.info/LongDivision/How-to-calculate-98/divided-by-8-using-long-division.html
Answer:
Step-by-step explanation:
Midpoint: (0,3)
Endpoint: (6,-3)
Use the midpoint formula:
Since you already have the midpoint and you need an endpoint, let the unknown endpoint be (x,y). Take the midpoint formula apart:
and 
are the coordinates of the midpoint. Enter the known values of the midpoint into the equations:
Now enter the known endpoint values:
Solve for x. Multiply both sides by 2:
Subtract 6 from both sides:
Now solve for y. Multiply both sides by 2:
Add 3 to both sides:
Now take the values of x and y and turn into a point:
Finito.
Work inside the brackets first, and then you can multiply the two equations if they are able to be mutiplied...
