The way that real-time text or RTT on her phone can help her is that;
C: On phone calls, it will convert speech into text
<h3>Speech to Text</h3>
We are told that Deirdre has a hearing disability. This means that she has difficulty in hearing words clearly but can read.
Thus, from her friends advice about real time text or RTT, it will aid her because whenever someone calls her on the phone, it can convert the content of the call speech into text.
The missing options are;
A. It will make her phone vibrate to notify her when she gets a phone call
B. It will make her phone vibrate to notify her when she gets a text message.
C. On phone calls, it will convert speech into text. D. While text messaging, it will convert text into speech
Read more on speech to text at; brainly.com/question/2375490
Solution :
#include
#include
#include
//Converts
to binary string.
* hexadecimal
Binary(char* hexdec)
{
long
= 0;
char *string =
(sizeof(char) * 9);
while (hexdec[i]) {
//Simply assign binary string for each hex char.
switch (hexdec[i]) {
strcat(string, "0000");
break;
strcat(string, "0001");
break;
strcat(string, "0010");
break;
strcat(string, "0011");
break;
strcat(string, "0100");
break;
strcat(string, "0101");
break;
strcat(string, "0110");
break;
strcat(string, "0111");
break;
strcat(string, "1000");
break;
strcat(string, "1001");
break;
case 'A':
case 'a':
strcat(string, "1010");
break;
case 'B':
case 'b':
strcat(string, "1011");
break;
case 'C':
case 'c':
strcat(string, "1100");
break;
case 'D':
case 'd':
strcat(string, "1101");
break;
case 'E':
case 'e':
strcat(string, "1110");
break;
case 'F':
case 'f':
strcat(string, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
string="-1" ;
}
i++;
}
return string;
}
int main()
{ //Take 2 strings
char *str1 =hexadecimalToBinary("FA") ;
char *str2 =hexadecimalToBinary("12") ;
//Input 2 numbers p and n.
int p,n;
scanf("%d",&p);
scanf("%d",&n);
//keep j as length of str2
int j=strlen(str2),i;
//Now replace n digits after p of str1
for(i=0;i<n;i++){
str1[p+i]=str2[j-1-i];
}
//Now, i have used c library strtol
long ans = strtol(str1, NULL, 2);
//print result.
printf("%lx",ans);
return 0;
}
Answer:
B. emotional
Explanation:
An emotional argument. An argument does not always have to be made in words.
Answer:
Following is attached the solution of each part step-by-step. I hope it will help you!
Explanation: