Answer:
Maybe try doing it earlier, don’t try doing things last minute it will put too much stress. Thank you :)
Step-by-step explanation:
Awnser is A 6+4 divided by [2+1]x3
-8
f(x) is y, in which x is the independent variable
when x = 5, y = -8
The solution for this problem is:
We know the problem has the following given:
Sample size of 200
X = 182
And the probability of .9005; computation: 1 - .0995 = .9005
So in order to get the probability:
P (x >= 182) = 1 – 0.707134 = .292866 is the probability
that when 200 reservations
are recognized, there are more passengers showing up than there
are seats vacant.
The other solution is:
p (>= 182) = p(183) +
P(184) + P(185) + ... + P(199) + P(200) = 0.292866
