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3 years ago

Ayoo if dia makes any sense plz help u needa find the domain an range of #1 #2 an #3.. Just unit 10........

Mathematics

1 answer:

Nookie1986 [14]3 years ago

4 0

Dead asl (can't keep replying stop blowing my shii up)

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What is the mode for the following set of data? 2, 5, 7, 8, 11, 11, 12

aleksley [76]

Mode = 11

Reason: 11 appeared twice, which is the most frequent number observed in this set of data.

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3 years ago

If 3:y=18:24 find y.

VashaNatasha [74]

y = 4

Explanation: $\begin{gathered} 3\text{ : y = 18 : 24} \\ 3\colon y\text{ = }\frac{3}{y} \\ 18\colon24\text{ = }\frac{18}{24} \end{gathered}$ $\begin{gathered} \frac{3}{y}\text{ = }\frac{18}{24} \\ \text{cross mult}iply\colon \\ 3(24)\text{ = y(18)} \\ \text{divide both sides by 18:} \\ \frac{3(24)}{18}\text{ = }\frac{18y}{18} \end{gathered}$ $\begin{gathered} y\text{ = }\frac{24}{6} \\ y\text{ = 4} \end{gathered}$

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1 year ago

Manuel bought a balloon (that is a perfect sphere) with a radius of 2 cm. He wanted his balloon to be bigger, so he blew 2 big b

horsena [70]

What is the question asking?

5 0

2 years ago

Read 2 more answers

The vector v⃗ in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

allsm [11]

The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis is: (0, -1/2, √3/2).

<h3>Vector</h3>

a. Vector (v)

Vector (v)=v (cos Ф, sin Ф)

V=1 while the counterclockwise angle that is measured from positive x=Ф=π/4

Hence:

Vector=3(cos π/4, sinπ/4)

Vector=(3/√2, 3√2)

b. Vector w:

Vector w=1(0, cos 2π/3, sin2π/3)

Vector w=(0, -1/2, √3/2)

Therefore the vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector ws: (0, -1/2, √3/2).

The complete question is:

Resolve the following vectors into components:

a. The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

(b) The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis.

Learn more about vector here:brainly.com/question/25705666

#SPJ1

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1 year ago

Find the least common multiple of these two expressions. 15x^7y^3u^8 and 6y^4u^5

snow_tiger [21]

Answer:

$30x^7y^4u^8$

Step-by-step explanation:

We have been given two expressions $15x^7y^3u^8$ and

$6y^4u^5$

Now we need to find out least common multiple of these two expressions.

First we need to find out what is common factor of both expressions. $15x^7y^3u^8$ and

$6y^4u^5$

Least common multiple means find the expression which can be divided by both expressions.

15 and 6 both goes into 30

so 30 is part of LCM (least common multiple )

Now pickup the highest exponent of each variable.

So we get $x^7y^4u^8$

Hence required least common multiple is $30x^7y^4u^8$

8 0

3 years ago