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cupoosta [38]
3 years ago
6

The time it takes Jessica to bicycle to school is normally distributed with mean 15 minutes and variance 4. Jessica has to be at

school at 8:00 am. Suppose you saw her at class, and she said it took her 23 minutes to get to school that day. Which of the following is a reasonable inference or conclusion?a. Twenty-three minutes to school is not an unusually long commute time.b. A commuting time of 23 minutes is highly unusual or atypical.c. The distribution of commute times MAY NOT be normal with mean 15 minutes and standard deviation 2 minutes.d. Both (b) and (c) are feasible conclusions.e. Both (a) and (c) are feasible conclusions.
Mathematics
1 answer:
exis [7]3 years ago
4 0

Answer:

d. Both (b) and (c) are feasible conclusions

Step-by-step explanation:

Given that the time  it takes Jessica to bicycle to school is normally distributed with mean 15 minutes and variance 4.

i.e. X the time it takes for Jessica to reach school is N(15,2)

One day Jessica said it took 23 minutes to get to school

i.e. 4 std deviations above the mean time it took

the prob for this is almost 0 which is very unusual.

Either the distribution is not symmetric as mentioned normal or the time is unusual

Hence correct option woul dbe

b. A commuting time of 23 minutes is highly unusual or atypical. and

c. The distribution of commute times MAY NOT be normal with mean 15 minutes and standard deviation 2 minutes

So both b and c are feasible conclusions

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 (5
Blizzard [7]

Answer:

B = 61.75°

Step-by-step explanation:

The formula for the Law of Sines is given as:

a/ sin A = b/ sin B

In the question, we are given the following values

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We are to solve for B

Hence,

16/ sin 56° = 17/sin B

Cross Multiply

sin B × 16 = sin 56° × 17

sin B = sin 56° × 17/16

sin B = 0.88

B = arc sin(0.88)

B = 61.74536°

Approximately B = 61.75°

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I walked forward 5m, back 3m, then forward 7m what is my displacement
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10 points please answer correctly (due soon)
luda_lava [24]

The exponential equation of the model is A(t) = 2583 * 0.88^t and the multiplier means that the number of new cases in a week is 88% of the previous week

<h3>The function that models the data</h3>

The given parameters are:

New, A(t) = 2000

Rate, r = 12%

The function is represented as:

A(t) = A * (1 - r)^t

So, we have:

2000 = A * (1 - 12%)^t

This gives

2000 = A * (0.88)^t

2 weeks ago implies that;

t = 2

So, we have:

2000 = A * 0.88^2

Evaluate

2000 = A * 0.7744

Divide by 0.7744

A = 2583

Substitute A = 2583 in A(t) = A * 0.88^t

A(t) = 2583 * 0.88^t

Hence, the exponential equation of the model is A(t) = 2583 * 0.88^t

<h3>The interpretation of the multiplier</h3>

In this case, the multiplier is 88% or 0.88

This means that the number of new cases in a week is 88% of the previous week

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2 years ago
B&gt;13/9 interval notation
BartSMP [9]
Interval Notation of b > 13/9 is [13/9, infinity)
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