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SIZIF [17.4K]
3 years ago
14

Paul bought a soft and a sandwich for $9.90. What equation may be used to find the price of each item if the sandwhich cost 3.5

times as much as the soft drink
Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

Sandwich costs $7.70 and the soda costs $2.20

Step-by-step explanation:

First create a ratio:


The sandwich cost 3.5 more than the drink therefore the ratio is 3.5:1


Then add the two sides of the ratio together to get the total parts of the ratio

3.5+1 = 4.5


Now that we know the total parts of the ratio we can solve for one part by dividing the total cost $9.90 by the total parts of the ratio 4.5+


$9.90/4.5 = 2.20


Since we know that each part of the ratio is 2.20 we multiply both sides of the ratio by 2.20


3.5 *2.20 = 7.70

1 * 2.20 = 2.20



Natasha2012 [34]3 years ago
7 0

The equation is 3.5x+x=9.9

The soft drink costs 2.2 and the sandwhich costs 7.7


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A cookie factory monitored the number of broken cookies per pack yesterday.
trapecia [35]

Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given  

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20  

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } } \leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }

confidence interval:

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