Answer:
Length 37 cm, width 25 cm.
Step-by-step explanation:
Let the original dimensions be length x and width x - 12 cms.
The new dimensions will be length (x - 2) and width (x - 12 - 2) = x-14 cm.
So , from the areas, we have:
x(x - 12) - (x - 2)(x - 14) = 120
x^2 - 12x - (x^2 - 16x + 28) = 120
-12x + 16x - 28 = 120
4x = 148
x = 37 cms
So the length was 37 cm and the width was 37-12 = 25 cm.
Answer:
F = 3x +(2.7×10^7)/x
Step-by-step explanation:
The formulas for area and perimeter of a rectangle can be used to find the desired function.
<h3>Area</h3>
The area of the rectangle will be the product of its dimensions:
A = LW
Using the given values, we have ...
13.5×10^6 = xy
Solving for y gives ...
y = (13.5×10^6)/x
<h3>Perimeter</h3>
The perimeter of the rectangle is the sum of the side lengths:
P = 2(L+W) = 2(x+y)
<h3>Fence length</h3>
The total amount of fence required is the perimeter plus one more section that is x feet long.
F = 2(x +y) +x = 3x +2y
Substituting for y, we have a function of x:
F = 3x +(2.7×10^7)/x
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<em>Additional comment</em>
The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.
Answer:
90yd
Step-by-step explanation:
to find the area you have to do base times height so it is 6x15=90
3.2-3x+7
6-3x+7
-7 -7
-1= -3x divide both sides by -3
x=0.3
