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3 years ago

Help quickly pls area of a triangle: sine formula

Mathematics

1 answer:

AysviL [449]3 years ago

4 0

Answer:

If you were to use the sine formula you would have to use the cosine formula to get one of the opposite sides and then use the sine formula.

For the area why not use 1/2 * 20 to get the base.

Then the height would be 24 * sin 63 = 21.38

That would give an area of 213.8

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Consider points a, b, and c in the graph below. Determine which of these points are relative maxima on the interval x = –4 to x

KonstantinChe [14]

Answer:

Step-by-step explanation:

Like I said in my previous answer, you have to look at the point that kinda "pokes out" of the graph, which in the interval (-4,0) is a and b

7 0

3 years ago

Read 2 more answers

Find the value of the determinant using the method of expansion by minors; expand on the third row

valkas [14]

For the matrix

$\begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}$

the determinant using the method of expansion by minors, expanding on the third row is:

$\det \begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}=a_{31}\det \begin{bmatrix}{a_{12}} & {a_{13}} & {} \\ {a_{22}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}-a_{32}\det \begin{bmatrix}{a_{11}} & {a_{13}} & {} \\ {a_{21}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}+a_{33}\det \begin{bmatrix}{a_{12}} & {a_{12}} & {} \\ {a_{22}} & {a_{22}} & {} \\ {} & {} & {}\end{bmatrix}$

Answer:

First, we compute the determinants of the minors:

$\begin{gathered} \det \begin{bmatrix}{0} & {4} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=0+4=4, \\ \det \begin{bmatrix}{1} & {4} & {} \\ {1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=3-4=-1, \\ \det \begin{bmatrix}{1} & {0} & {} \\ {1} & {-1} & {} \\ {} & {} & {}\end{bmatrix}=-1-0=-1. \end{gathered}$

Therefore:

$\det \begin{bmatrix}{1} & {0} & {4} \\ {1} & {-1} & {3} \\ {0} & {5} & {-2}\end{bmatrix}=0\times4-5\times(-1)+(-2)\times(-1)=5+2=7.$

3 0

1 year ago

Polygon B BB is a scaled copy of Polygon A AA using a scale factor of 5 55. How many times larger is the area of Polygon B BB th

stira [4]

Answer:

308025 times larger

Step-by-step explanation:

The polygon BBB is a scaled copy of polygon A using a scale factor of 555.

This means for every length of polygon AAA, polygon BBB is 555 times larger.

Recall area is in $L^{2}$ .

Area of polygon BBB = (scale factor)^2 multiplied by area of polygon AAA

Since the scale factor is 5

Area of polygon BBB = (555^2) * Area of polygon AAA

Area of polygon BBB = 308025 times the area of polygon AAA

Hope I have been able to help.

8 0

3 years ago

Read 2 more answers

The first right answer gets brainlyist. Thanks

natita [175]

This is because “trig” solves for the missing angles in a right angled triangle and does not solve for the sides of a right angle triangle.

Hope this helps :)

7 0

3 years ago

Triangle ABC is similar to triangle WYZ.

Inga [223]

9514 1404 393

Answer:

False

Step-by-step explanation:

Corresponding angles in similar triangles are congruent. The similarity statement tells you angle B corresponds to angle Y, so those angles are congruent. The sines of congruent angles are identical.

sin(B) > sin(Y) . . . . FALSE

sin(B) = sin(Y) . . . . true

7 0

3 years ago