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Ainat [17]
3 years ago
10

A line pssses through the points (6,5) and (2,2)

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0
Take y2-y1 over x2-x1 to get the slope of the line
2-5/2-6
-3/-4
3/4
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Stu Reese has a $150,000 7½% mortgage. His monthly payment is $1,010.10. His first payment will reduce the principal to an outst
BabaBlast [244]

Given that

starting outstanding balance = $150000

rate of interest = 7.5% per year

so rate of interest for 1 month = (7.5/12)% = 0.635%

outstanding balance before 1st monthly payment =  starting outstanding balance   +   0.625% of interest on  starting outstanding balance

= 150000 + (0.625 /100) × 150000

= 150000 + 937.5 = $150937.5

Reduction = outstanding balance after one month - first monthly payment

Reduction  = $150937.5 - 1010.10 = 149927.40

so out of first payment of $1,010.10 ,  $937.5  goes towards interest and remaining $72.6 goes towards reduction of principal that is 150000 - $72.6 = 149927.40.

so correct option is B that is $149927.40.

8 0
3 years ago
What is the slope of the line in the graph below?
Ivahew [28]

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>

8 0
3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666

Second step. <u>Calculate the standard deviation</u>

\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}

\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}

\sigma=\sqrt{17.815}=4.22

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).  

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

\bar X \pm t\frac{\sigma}{\sqrt n}

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0
3 years ago
Can someone help me and show your work thanks
GREYUIT [131]

Answer:

D) $8.20

Step-by-step explanation:

82 x 0.1 = 8.2

4 0
3 years ago
Read 2 more answers
GEOMETRY HELP PLEASE!!!!!!!!!!!
Setler [38]
I have the same problem. if i find the answer i will give it to you

8 0
3 years ago
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