W - a width
3w - a length
27 ft² - an area

Therefore:

w · 3w = 27
3w² = 27 |:3
w² = 9 → w = √9 → w = 3

3w = 3 · 3 = 9

width = 3
length = 9

The perimeter:

P = 2 · width + 2 · length

P = 2 · 3 + 2 · 9 = 6 + 18 = 24 ft.

3 0

3 years ago

Helpp with this for me pls due tomarrow

Zielflug [23.3K]

Answer:

14/3 - 4 and 2/3

35/8- 4 and 3/8

51/12- 4 and 3/12

22/5- 4 and 2/5

Step-by-step explanation:

8 0

3 years ago

Y - 3 = 2(x + 1)

Natalija [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

2 years ago