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yaroslaw [1]
2 years ago
8

Two sides of a triangle are 12cm and 8cm. Complete the inequality to show the possible lengths for the third side. If the third

side of the triangle is x then, _
Mathematics
1 answer:
Nookie1986 [14]2 years ago
4 0

The inequalities that represents the third side of the triangle is  x ≥ 4 or x ≤ 20

How to find the third side of a triangle?

The triangle inequality theorem states that that the sum of any two sides of a triangle is greater than or equal to the third side.

Therefore, the two sides of the triangle are 12 cm and 8 cm.

A triangle with sides a, b and x follows the principle below;

a + b ≥ x.

Therefore,

let

x = third sides

12 + 8 ≥ x

20 ≥ x

x + 8 ≥ 12

x ≥ 4

x + 12 ≥ 8

Therefore, the third third should be greater than or equals to 4 or less than or equals to 20

x ≥ 4 or x ≤ 20

learn more on triangle here:

brainly.com/question/28105571

#SPJ1

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5 0
3 years ago
Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^
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e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}

STEP 3: Get the equation of the ellipse

\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

\frac{x^2}{144}+\frac{y^2}{95}=1

OPTION A

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1 year ago
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Marta_Voda [28]

Answer:

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Step-by-step explanation:

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Answer

Step-by-step explanation:

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