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2 years ago

PLS PLS PLS PUT THIS ON THE NUMBER LINE FROM LEAST TO GREATEST !!!!!!! I WILL GIVE BRAINLIESST!

Mathematics

2 answers:

Digiron [165]2 years ago

4 0

Answer:

Where's the number line?

Step-by-step explanation:

brilliants [131]2 years ago

3 0

Answer:

no number line. cant help pls repost your question

Step-by-step explanation:

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I need help.. with this worksheet

ipn [44]

8. $298 4. 250 9. 28 6. 8.7 5. 465

3 0

3 years ago

The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.

Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If $Z \leq -2$ or $Z \geq 2$ , the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1$

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{19 - 22}{1}$

$Z = -3$

$Z = -3 \leq -2$ , so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0

3 years ago

Please explain this to me!

Charra [1.4K]

One meaning of a 'linear' equation is that if you draw the graph
of the equation, the graph will be a straight line.

That's an easy way to test the equation . . . find 3 points on the
graph, and see whether they're all in a straight line.

This equation is y = 4 / x .

To find a point on the graph, just pick any number for 'x',
and figure out the value of 'y' that goes with it.
Do that 3 times, and you've got 3 points on the graph.

Here ... I'll do 3 quick points:

Point-A: x = 1 y = 4 / 1 = 4
Point-B: x = 2 y = 4 / 2 = 2
Point-C: x = 4 y = 4 / 4 = 1

Look at this:

Slope of the line from point-A to point-B
= (change in 'y') / (change in 'x') = -2 .

Slope of the line from point-B to point-C
= (change in 'y') / (change in 'x') = -1/2 .

The two pieces of line from A-B and from B-C don't even have
the same slope, so they're not pieces of the same straight line !
So my points A, B, and C are NOT in a straight line.

So the equation is NOT linear.

Try it again with three points of your own.

5 0

3 years ago

√a=-2 find the extraneous solution

Hunter-Best [27]

A=4 because √a=-2 the you square each side to make it a=4.

6 0

3 years ago

At a recent job fair, Intel boasted that they paid master's graduates more than 90% of all

ankoles [38]

Complete Question

A recent study found that hourly wages earned by employees possessing a master's degree are distributed normally with a mean of $27.50 and standard deviation of $3.50

At a recent job fair, Intel boasted that they paid master's graduates more than 90% of all

employers. If we interpret their claim as a percentile, what hourly wage must they offer employees with master's degrees?

Answer:

The value is $x = \$31.986$