WILL MARL BRAINLEST

A company tests all new brands of golf balls to ensure that they meet certain specifications. One test conducted is intended to

docker41 [41]

Answer:

385 golf balls

Step-by-step explanation:

margin of error = (z*)(s) / sqrt n

where z* = 1.96 with 5%/ 2 = 0.025 area in each tail

margin of error = (z*)(s) / sqrt n

1.2 yards = (1.96)(12 yards) / sqrt n

solve for n

n = 384.16

385 golf balls (always round up)

3 0

3 years ago

A recipe needs 4 cups of milk and 6 cups of grated cheese. what is the ratio of the number of cups of grated cheese in the recip

ryzh [129]

The correct answer is A) 2:3 because 4/6 simplified is 2/3

5 0

3 years ago

Cydus<br> How many solutions doos the equation 4+4x - 3=4x +5 have?

ipn [44]

0 solutions because simplifying the equation gives us 1 = 5, which is never true

5 0

3 years ago

Read 2 more answers

Two planes leave an airport at the same time. Thier speeds are mph 130 and 150 mph, and the angle between thier courses is 36 de

Reil [10]

Answer:

132.89 miles

Step-by-step explanation:

Let plane A travel at 130 mph and plane B travel at 150 mph.

After 1.5 hours, the total distance traveled by each plane is:

$A = 1.5 *130\\A = 195\ miles\\B = 1.5 *150\\B = 225\ miles$

The law of cosines can be used to find the distance (D) between both planes as follows:

$D^2 = A^2+B^2-2AB*cos(36)\\D=\sqrt{195^2+225^2-(2*195*225*cos(36))}\\D=132.89\ miles$

They are 132.89 miles apart after 1.5 hours.

5 0

3 years ago

The cable between two towers of a suspension bridge can be modeled by the function shown, where x and y are measured in feet. Th

hodyreva [135]

a) x = 200 ft

b) y = 50 ft

c)

Domain: $0\leq x \leq 400$

Range: $50\leq y \leq 150$

Step-by-step explanation:

a)

The function that models the carble between the two towers is:

$y=\frac{1}{400}x^2-x+150$

where x and y are measured in feet.

Here we want to find the lowest point of the cable: this is equivalent to find the minimum of the function $y(x)$ .

In order to find the minimum of the function, we have to calculate its first derivative and require it to be zero, so:

$y'(x)=0$

The derivative of y(x) is:

$y'(x)=\frac{1}{400}\cdot 2 x^{2-1}-1=\frac{1}{200}x-1$

And requiring it to be zero,

$\frac{1}{200}x-1=0$

Solving for x,

$\frac{1}{200}x=1\\x=200 ft$

b)

In order to find how high is the road above the water, we have to find the value of y (the height of the cable) at its minimum value, because that is the point where the cable has the same height above the water as the road.

From part a), we found that the lowest position of the cable is at

$x=200 ft$

If we now substitute this value into the expression that gives the height of the cable,

$y=\frac{1}{400}x^2-x+150$

We can find the lowest height of the cable above the water:

$y=\frac{1}{400}(200)^2-200+150=50 ft$

Therefore, the height of the road above the water is 50 feet.

c)

Domain:

The domain of a function is the set of all possible values that the independent variable x can take.

In this problem, the extreme points of the domain of this function are represented by the position of the two towers.

From part a), we calculated that the lowest point of the cable is at x = 200 ft, and this point is equidistant from both towers. If we set the position of the tower on the left at

$x=0 ft$