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3 years ago

The width of a rectangle is 15 cm and the perimeter is 72 cm. Find the length.

Mathematics

2 answers:

ale4655 [162]3 years ago

8 0

Answer:

Step-by-step explanation:

Jobisdone [24]3 years ago

4 0

Answer:

the length is 21cm

Step-by-step explanation:

15*2=30

72-30=42

42/2=21

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R-12 evaluate if r= negative 3

GalinKa [24]

If r=-3, then it would be -3-12 which equals -15

5 0

4 years ago

creativ13 [48]

Step-by-step explanation:

since the house, the school and the grocery store all have the same x coordinate (-4), they are on the same vertical line of x = -4.

and that means their distances are simply the differences in their y coordinates.

the only one different in that regard is the community center, but it is on the same y coordinate as the school, so the distance to the school is only the difference in their x coordinates.

so, the distance from house to school is

|5 - 3| = |3 - 5| = 2

as it is the same distance in either direction.

the distance from house to school to grocery store is the distance from house to school plus the distance from school to grocery store :

2 + |3 - -9| = 2 + |-9 - 3| = 2 + 12 = 14

now we need to find the distance from home to school to community center.

that is 2 + the distance from school to community center.

as mentioned above, since the school and the community center have the same y coordinate, their distance is the difference in their x coordinates :

|-4 - 6| = |6 - -4| = 10

so, in total the way house to school to community center is 2 + 10 = 12.

and that is shorter than the way house to school to grocery store, which is 14.

so, yes, the distance house to school to grocery store (14) is greater than the distance house to school to community center (12).

8 0

3 years ago

Solve for X. show your work. (x+2)(x+8)=0

valentinak56 [21]

Step-by-step explanation:

x = -2

x = -8

please follow me

3 0

3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.