(x - 1/6)(x - (-2/3)) = 0
(x - 1/6)(x + 2/3) = 0
x^2 + 2/3x - 1/6x - 1/6(2/3) = 0
x^2 + 1/2x - 1/9 = 0
18x^2 + 9x - 2 = 0
For the whole thing including the other point it would be [-6, 6] but just for f it should be [6]
Yes, it is true (I’m pretty sure, same shape etc)