Answer:
0.04
Step-by-step explanation:
Given that a dart is to be thrown at a target. The probability the dart will hit the target (yes or no) on a single attempt is 0.20
Each throw is independent of the other throws.
Let x be the no of times the target is hit in the trial of 4 throws
Since each outcome is independent of the other X is binomial with n =4 and p = 0.20
Required probability
= the probability that it will take less than or equal to 4 throws to hit the target on both successful target hits
=P(X=2 when n =2) + P(x=2 when x =3) + P(x=2 when x =4)
=