All categories

3 years ago

Francine is playing a board game with her friends. She needs to roll two dice

Mathematics

2 answers:

fgiga [73]3 years ago

8 0

Answer:

No.of pairs for which she will get a pair grater tha 10 =2 (6,6; 5,6 )

total pairs =12

Probability of not winning= (12-2)/12

=10/12

=5/6

damaskus [11]3 years ago

5 0

10/12 = 5/6 probability that she will not win on the next roll

You might be interested in

Tan(-x) cos(-x) =<br><br> Simplify the expression

Tamiku [17]

Answer:

- sin (x)

Step-by-step explanation:

hope this helps :)

8 0

3 years ago

Read 2 more answers

Can someone please help? i’ll make you a brainliest.

Darya [45]

Answer:

Step-by-step explanation:

4 0

3 years ago

He equation shows the relationship between x and y:

son4ous [18]

Answer:

-7

Step-by-step explanation:

y=-7x+9

y=mx+b

m=slope

y=y-intercept

5 0

3 years ago

Joan has earned grades of 88, 94, 92, and 98 on math tests so far. What must her next grade be to give her an average grade of 6

Ira Lisetskai [31]

Answer:

see the explanation

Step-by-step explanation:

Let

x ------> the next grade

we know that

To find the average grade sum the grades by the number of math test

$60=\frac{(88+94+92+98+x)}{5}$

solve for x

Combine liker terms in the right side

$60=\frac{(372+x)}{5}$

Multiply by 5 both sides

$300=372+x$

Subtract 372 both sides

$300=372+x$

$x=-72$ -----> this is not make sense

The grade cannot be a negative number

For x=0

The minimum average grade is

$\frac{(372)}{5}=74.4$

3 0

3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago