The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.
<h3>Can this atrium be built in the rectangular plot of land?</h3>
The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.
First, we calculate the volume occupied by the maximum allowable radius:
<em>V' =</em> (8 · π / 3) · (45 ft)³
<em>V' ≈</em> 763407.015 ft³
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. 
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The answer to the problem is obvious it’s BLANK
Answer:
-10 3
-9 4
-8 5
-3 10
Step-by-step explanation:
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Answer:
x > 4.5
Step-by-step explanation:
Given the inequality :
14.4x - 28.2 > 36.6
Collect like terms
14.4x > 36.6 + 28.2
14.4x > 64.8
Divide both sides by 14.4
x > 64.8 / 14.4
x > 4.5
The dimensions of the rectangle are 150 m and 75 m respectively.
Let x be the length of the rectangular area and y be the width of the rectangular area.
Its area A = xy
Given that its area is 11,000 m², xy = 11000 m² (1)
Also, since the bounding side of the building is 150 m long and the fencing is 300 m, the perimeter of the rectangular area is P = 150 m + 300 m = 450 m.
Also, the perimeter of the rectangular area is P = 2(x + y)
Since P = 450 m
2(x + y) = 450 m
x + y = 225 m (2)
Since the bounding side of the building represents one dimension of the rectangle, x = 150 m.
Substituting x into (2), we get the other dimension
x + y = 225
150 + y = 225
y = 225 m - 150 m
y = 75 m
So, the dimensions of the rectangle are 150 m and 75 m respectively.
Learn more about dimensions of a rectangular area here:
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