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Kobotan [32]
3 years ago
14

if michelle rollerblade around a circular track with a radius of 80 meters, how far does she skate? use 3,14 for pie. round to t

he nearest tenth
Mathematics
1 answer:
crimeas [40]3 years ago
4 0
Circumference of a circle formula is 2\pir

2 × \pi × 80
=160 × <span>\pi 
=502.4 m

She skates 502.4 m.</span>
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Find the gradient of the line segment between the points<br> (-1,2) and (-2,3).
Svetach [21]

Answer:

The gradient of the line segment between the two points is -1

Step-by-step explanation:

The gradient of the line segment between two points is also known as the slope,

We  can find this by using the formula; y₂ - y₁ /  x₂ - x₁

The points given to us are;(-1,2) and (-2,3).

This implies x₁ = -1  ,     y₁=2         x₂ =  -2        y₂= 3

We can now proceed to insert our values into the formula;

Gradient = y₂ - y₁ /  x₂ - x₁

                = 3 - 2  /  -2-(-1)

                 = 1  /  -2 + 1

                  =1/-1

Gradient = -1

Therefore the gradient of the line segment between the two points is -1

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Step-by-step explanation:

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One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

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