Answer:
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Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
The expression should be (2/h)x(k+8).
Answer:
x > 1
Step-by-step explanation:
Subtract 3 from both sides
8x + 3 - 3 > x + 10 - 3
Simplify
8x > x + 7
Subtract x from both sides
8x - x > x + 7 - x
Simplify
7x - 7
Divide both sides by 7
7x/7 > 7/7
Simplify
x > 1
