Juan takes 15 hours to do a job that his father can do in 6 hours. If juan works for 4.5 hours before his father joins him, how
long will it take the two of them working together to finish the job?
1 answer:
Work it exactly like the other one with Wilda and Karla.
Juan takes 15 hours to do a job ... he does 1/15 of it in an hour.
His father can do it in 6 hours ... he does 1/6 of it in an hour.
Juan works alone for 4.5 hours. In that time, he does 4.5/15 = 0.3
of the job. When his father joins him, there's only 0.7 of it to finish.
Working together, they do (1/15 + 1/6) = (2/30 + 5/30) = 7/30 of the job
each hour.
How many times do they have to do 7/30 of the job in order to finish
the 7/10 of it that remains ? That will be the number of hours they need.
(7/10) / (7/30) = 7/10 x 30/7 = <em>3 hours</em>.
Then they can knock off while it's still daylight, and go for a swim.
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Answer:
2*2*3*3*5
Step-by-step explanation:
180 = 18*10
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= 6*3 * 5*2
3,5,2 are prime but 6 is composite
= 3*2 * 3 * 5 * 2
All the factors are prime
Listing in order
2*2*3*3*5
If the answer your looking for is a graph then yeah
The answer would be -17.6.
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The answer is d i got it right message me