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tekilochka [14]
3 years ago
5

I think it’s b but I’m not sure but can somebody help me

Mathematics
1 answer:
aev [14]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The small triangle is half the size of the entire triangle. 27/2 = 13.5

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GEOMETRY: PLEASE HELP!!
Aloiza [94]

Answer:

GF=72

Step-by-step explanation:

All triangles in the given figure are similar, from SAS. Notice that marked in the diagram, CD=DE=EF=FA.

For triangle \triangle CGF was base GF, leg CF contains three of these marked segments. In triangle \triangle CHE with base HE, leg CE has two of these marked segments. By definition, similar polygons have corresponding sides in a constant proportion. Therefore, the length of GF must be 3/2 the length of EH. Since the length of EH is given as 48, we have:

GF=\frac{3}{2}EH, \\\\GF=\frac{3}{2}\cdot 48,\\\\GF=\boxed{72}

7 0
3 years ago
In April, The Kazbaas drove 760 miles in their tour van.
DedPeter [7]

9514 1404 393

Answer:

  £135.98

Step-by-step explanation:

  (760\text{ mi})\dfrac{1\text{ gal}}{29.5\text{ mi}}\cdot\dfrac{4.55\text{ L}}{1\text{ gal}}\cdot\dfrac{\pounds1.16}{1\text{ L}}=\dfrac{760\cdot4.55\cdot\pounds1.16}{29.5}\\\\=\boxed{\pounds135.98}

It cost £135.98 for petrol in April.

5 0
3 years ago
Use four rectangles to estimate the area between the graph of the function f(x) = V3x + 5 and the x-axis on the interval[0, 4] u
yuradex [85]

Answer:

  12.123

Step-by-step explanation:

You want the area under the curve f(x) = √(3x+5) on the interval [0, 4] estimated using the left sum and four subintervals.

<h3>Riemann sum</h3>

When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

The area we want is the sum ...

  f(0) +f(1) +f(2) +f(3)

As the attachment shows, that sum is ...

  area ≈ 12.123 . . . square units

__

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

Such a sum is called a Riemann sum, named for a German mathematician. Four such sums are commonly used, and further refinements are possible. Those are the left sum (as here), the right sum, the midpoint sum, and a sum using a trapezoidal approximation of the rectangle area.

For left, right, and midpoint sums, n function values are required for n subintervals. When the trapezoidal approximation is used, n+1 function values are required.

7 0
1 year ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
A bottle is filled with saline solution for eyes, is the bottle more likely to hold 15 milliliters of solution or 1 liter of sol
Gnesinka [82]
The bottle is more likely to hold 15 milliliters

hope this helped
3 0
3 years ago
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