Rational numbers are the numbers that can be written as the fraction of two integers and absolute value is the distance a number is away from 0. If we look at a number line, the absolute value is the distance any number on the number line is away from 0. Distance is always positive, so our absolute value is always 0.
Answer:
1/6
Step-by-step explanation:
Well perpendicular lines are reciprocals of each other,
meaning if like k has a slope of -6 then line n will have a slope of positive 1/6.
<em>Thus,</em>
<em>line n has a slope of 1/6.</em>
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<em>Hope this helps:)</em>
Answer:
first year $20 second year $20.80 Third year $21.63
Step-by-step explanation: This is for an extra money per year so after the first year that is how much extra money he gets every year.
The answer is AA
good luck
Answer:
Step-by-step explanation:
Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).
- Brown:

- Yellow or Blue:
....add the numerators
- Not Green:
.... since the sum of all the rest is 80%
- Stiped:
.... there are 0 striped candies.
Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.
- 3 Browns:

- the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

- None are Yellow: multiply the percent of all minus yellow three times.

- At least 1 green: multiply the percent of green by 100% twice, since the other two can by any
