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nasty-shy [4]
3 years ago
11

Plz help me do this homework

6ac - 15ad - 8bc + 2bd" alt="6ac - 15ad - 8bc + 2bd" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ahat [919]3 years ago
7 0

The given polynomial is

→ 6 ac - 15 a d- 8 b c + 2 b d

→ 3× 2×a×c - 3×5×a×d - 2×2×2× b×c + 2×b×d

→ 3 a ( 2 c -5 d)  - 2 b(4 c -d)

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Please answer!
Xelga [282]

Amswer

it is b Step-by-step explanation:

8 0
3 years ago
What is 13 times 13 my little brother wants to know I told him let you guys help!!
Oksi-84 [34.3K]

Answer:

13 times 13 is 169

Step-by-step explanation:

I did it by doing it in my head

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5 0
3 years ago
Read 2 more answers
Solve the equations
ASHA 777 [7]

Answer:

(1)The value of x is -9 .

Option (B) is correct .

(2)The value of x is 13 .

Option (A) is correct .

(3)The value of the x is 11 .

Option (D) is correct .

(4) The value of the x is -15 .

Option (A) is correct .

(5)The value of the x is -11 .

Option (C) is correct .

Step-by-step explanation:

First Part

As given

4x = -36

x = \frac{-36}{4}

x = -9

Therefore the value of x is -9 .

Option (B) is correct .

Second Part

As given

5x - 15 = 50

5x = 50 + 15gg

5x = 65

x = \frac{65}{5}

x = 13

Therefore the value of x is 13 .

Option (A) is correct .

As given

4(x+2)-17=35

4x + 8 - 17 = 35

4x = 35 + 17 - 8

4x = 44

x = \frac{44}{4}

x = 11

Therefore the value of the x is 11 .

Option (D) is correct .

Fourth Part

As given

6x+12=4x-18

6x-4x = -12-18

2x = -30

x = \frac{-30}{2}

x = -15

Therefore the value of the x is -15 .

Option (A) is correct .

Fifth Part

As given

\frac{1}{2}(4x-10)+5=x-11

Simplify the above

4x-10+5×2 = 2x-22

4x-10+10= 2x-22

4x-2x = -22

2x=-22

x = \frac{-22}{2}

x = -11

Therefore the value of the x is -11 .

Option (C) is correct .

5 0
3 years ago
Read 2 more answers
Solve equation.<br> k+3=14
lorasvet [3.4K]

To solve the equation, subtract 3 from both sides. The solution is k = 11.

A linear equation is an equation of which the highest degree of its variables is 1.

Steps to solve linear equations:

  1. Simplify the expressions. If there are parentheses, remove them by multiplying the corresponding terms.
  2. Combine the same terms.
  3. Isolate the variable on one side by using subtraction of addition.
  4. Use division or multiplication to find the value of the variable.

Recall that if  we subtract or add the same number to both sides of an equation, it does not change the equality.

The given problem:

Solve k + 3 = 14.

The variable is k. Subtract 3 from both sides:

k + 3 - 3 = 14 - 3

k = 11 (solved)

Learn more about solving an equation here:

brainly.com/question/25678139

#SPJ4

5 0
1 year ago
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
4 years ago
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