Because its a square all its sides are 5cm
So area of square is 5x5=25cm^2
Triangle is 5x4= 20
20/2 is 10cm^2
25+10=35cm^2
Answer:
(a) d = 0.012v^2
(b) 4.8 m
(c) 25 m/s
Step-by-step explanation:
(a) Writing an equation to fit a bunch of data is often a matter of trial and error. You can often get an idea of the sort of function that is involved by graphing the data points.*
When we do that, we see the relationship is non-linear with an upward curvature. It might be described by a polynomial or exponential function.
When we try a quadratic equation, we find the fit is really quite good. The graphing calculator that does this quadratic regression analysis tells us the equation is essentially ...
d = 0.012·v^2
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(b) The equation predicts a depth of 4.8 m.
d = 0.012·20^2 = 4.8
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(c) Solving for speed, we get a speed of 25 m/s.
7.5 = 0.012v^2
625 = v^2 . . . . . . divide by .012
25 = v . . . . . . . . . take the square root
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* The energy of a falling object is proportional to the square of its speed. If we assume that the depth of penetration into the clay is proportional to the energy absorbed, then it is not surprising to see a quadratic relationship between speed and distance. What is surprising is that this relationship would show up in middle school math problem, not a high-school physics problem.
Essentially, you have to assume the form of the equation, then find the coefficients that make it so. Working with the evenly spaced table values of 5, 10, 15 m/s can simplify the effort.
A graphing calculator or spreadsheet can do the bulk of the work once the data is entered.
Answer:
12
Step-by-step explanation:
one bowl is equal to 3 sundaes. When you count the number of bowls shown in the pictograph, there are 16 bowls. Now multiply 16 by 3 to know how many sundaes there are. Since there are 4 different stores, you would have to divide 48 by 4 to get your mean(or average) value.
Math:
16 x 3 = 48
48/4 =12
No not always, because x could be a smaller number than y which would make it an negative. If x is bigger than y most likely it will be, but not always.
On problems ii, and iii, you just count up the amount of sides on the polygon and add x behind it to create a type of an equation to find the perimeter of that shape that will work as longs as the sides are congruent to each other.
For problems a,b, and c, you just have to calculate what x is. On a, you find what the other side is if one side is 2 and the area is 24. On b you find what the other side could equal if one side is 4 and the area is 16. On c you know what the perimeter is (72) . The longer sides are 2x and the shorter sides are x. SO you divide by the #s and check your work!