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Lera25 [3.4K]
3 years ago
7

How do u do this stuff?

Mathematics
1 answer:
olga2289 [7]3 years ago
5 0
On problems ii, and iii, you just count up the amount of sides on the polygon and add x behind it to create a type of an equation to find the perimeter of that shape that will work as longs as the sides are congruent to each other. 
For problems a,b, and c, you just have to calculate what x is. On a, you find what the other side is if one side is 2 and the area is 24. On b you find what the other side could equal if one side is 4 and the area is 16. On c you know what the perimeter is (72) . The longer sides are 2x and the shorter sides are x. SO you divide by the #s and check your work!
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Step-by-step explanation:

<u />

<u>Geometric sequence</u>

General form of a geometric sequence: a_n=ar^{n-1}

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Given:

\displaystyle \sum^{20}_{n=1} 4 \left(\dfrac{8}{9}\right)^{n-1}

Therefore:

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<u>Sum of the first n terms of a geometric series</u>:

S_n=\dfrac{a(1-r^n)}{1-r}

To find the sum of the first 20 terms, substitute the found values of a and r, together with n = 20, into the formula:

\implies S_{20}=\dfrac{4\left(1-\left(\frac{8}{9}\right)^{20}\right)}{1-\left(\frac{8}{9}\right)}

\implies S_{20}=32.58609013...

\implies S_{20}=32.59\:\: \sf (nearest\:hundredth)                    

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