It does if the x values don't repeat it they repeat it doesn't
Answer with Step-by-step explanation:
We know that the components of velocity are obtained from position as
![u=\frac{dx}{dt}\\\\v=\frac{dy}{dt}](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bdx%7D%7Bdt%7D%5C%5C%5C%5Cv%3D%5Cfrac%7Bdy%7D%7Bdt%7D)
Using the given values we obtain
![u=\frac{d(2t^2)}{dt}\\\\u=4t](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bd%282t%5E2%29%7D%7Bdt%7D%5C%5C%5C%5Cu%3D4t)
Similarly
![v=\frac{d(t^2-41)}{dt}\\\\u=2t](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%28t%5E2-41%29%7D%7Bdt%7D%5C%5C%5C%5Cu%3D2t)
The the velocity function can be written as
![\overrightarrow{v}=4t\widehat{i}+2t\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D%3D4t%5Cwidehat%7Bi%7D%2B2t%5Cwidehat%7Bj%7D)
The components of acceleration are obatined from the components of velocity as
![a_{x}=\frac{du}{dt}\\\\a_{y}=\frac{dv}{dt}](https://tex.z-dn.net/?f=a_%7Bx%7D%3D%5Cfrac%7Bdu%7D%7Bdt%7D%5C%5C%5C%5Ca_%7By%7D%3D%5Cfrac%7Bdv%7D%7Bdt%7D)
Using the given values we obtain
![a_x=\frac{d(4t)}{dt}\\\\a_{x}=4](https://tex.z-dn.net/?f=a_x%3D%5Cfrac%7Bd%284t%29%7D%7Bdt%7D%5C%5C%5C%5Ca_%7Bx%7D%3D4)
Similarly
![a_y=\frac{d(2t)}{dt}\\\\a_y=2](https://tex.z-dn.net/?f=a_y%3D%5Cfrac%7Bd%282t%29%7D%7Bdt%7D%5C%5C%5C%5Ca_y%3D2)
The the acceleration function can be written as
![\overrightarrow{a}=4\widehat{i}+2\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%3D4%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D)
Thus at time 't=1' the velocity function becomes
![\overrightarrow{v}=4\widehat{i}+2\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D%3D4%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D)
Thus the component of acceleration in the direction of the given vector
can be found by taking the dot product of the 2 vectors
Thus we get
![v_{r}=\overrightarrow{v}\cdot \overrightarrow{r}\\\\v_{r}=(4\widehat{i}+2\widehat{j})\cdot (\widehat{i}-3\widehat{j})\\\\v_{r}=4-6=-2](https://tex.z-dn.net/?f=v_%7Br%7D%3D%5Coverrightarrow%7Bv%7D%5Ccdot%20%5Coverrightarrow%7Br%7D%5C%5C%5C%5Cv_%7Br%7D%3D%284%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D%29%5Ccdot%20%28%5Cwidehat%7Bi%7D-3%5Cwidehat%7Bj%7D%29%5C%5C%5C%5Cv_%7Br%7D%3D4-6%3D-2)
Similarly the dot product is obtained for acceleration as
![a_{r}=\overrightarrow{a}\cdot \overrightarrow{r}\\\\a_{r}=(4\widehat{i}+2\widehat{j})\cdot (\widehat{i}-3\widehat{j})\\\\a_{r}=4-6=-2](https://tex.z-dn.net/?f=a_%7Br%7D%3D%5Coverrightarrow%7Ba%7D%5Ccdot%20%5Coverrightarrow%7Br%7D%5C%5C%5C%5Ca_%7Br%7D%3D%284%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D%29%5Ccdot%20%28%5Cwidehat%7Bi%7D-3%5Cwidehat%7Bj%7D%29%5C%5C%5C%5Ca_%7Br%7D%3D4-6%3D-2)
Hello There!
In order to solve this problem, you would simply have to substitute F with the number you have been provided.
We do this because we want to determine the final output, which is y.
Without further ado, let's begin!
Replace F with the number provided.
59 - 32 = 27
Thus, 59 degrees Fahrenheit converted to celsius is 27 degrees.
Answer:
![103\ nickels](https://tex.z-dn.net/?f=103%5C%20nickels)
Step-by-step explanation:
Let
x------> the number of nickels
y-----> the number of dimes
we know that
![1\ nickel=\$0.05](https://tex.z-dn.net/?f=1%5C%20nickel%3D%5C%240.05)
![1\ dime=\$0.10](https://tex.z-dn.net/?f=1%5C%20dime%3D%5C%240.10)
![0.05x+0.10y=36.05](https://tex.z-dn.net/?f=0.05x%2B0.10y%3D36.05)
Multiply by 100 both sides
------> equation A
------> equation B
substitute equation B in equation A
Answer:
190 and 191 is that two consecutive numbers