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Pani-rosa [81]
3 years ago
14

The 7 a.m. flight from Dallas to Chicago is on time 75% of the time. Fran created this spinner to simulate the scenario.

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

CORRECT OPTION is (C) The flight will be late on one of the three days.

Step-by-step explanation:

The 7am flight from Dallas to Chicago is on time 75% of the time.

A spinner with four sections was created by Fran to simulate this scenario.

Since the 4 sections were equal, it means each section was 25% of the spinner.

3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.

This coincides with the 75% probability that the flight is on time on a given day.

In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.

Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:

- Shaded   - Shaded   - Unshaded

CORRECT OPTION is (C) The flight will be late on one of the three days.

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→ The circumference of the circle is: " 17.35 units " .

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The area, "A", of a circle:

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The area of the circumference, "C", of a circle:

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__________________________________________

Given:

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Use the formula for the area, "A" of a circle, to find the radius, "r" .

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To solve for the circumference, "C", of the circle.

________________

A = \pi  *  r^{2} ;

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↔ 3.14 * r² = 24 ;

Divide each side of the equation by "(3.14)" ;

[3.14 * r²] / 3.14 = (24) / (3.14) ;

to get:

→ r² = 7.64331210191 ;

Take the positive square root of each side of the equation;

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____________________________

Now, plug this "obtained value" for the radius, "r" into the equation for the formula for the circumference, "C" of a circle:

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to solve for the circumference, "C", of the circle:

→ C = 2 * (3.14) * (2.76281034802) ;

= (6.28) * (2.76281034802) ;

= 17.3504489856 ;

→ round to: " 17.35 units" .

__________________________________

The answer is: " 17.35 " .

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→ The circumference of the circle is: " 17.35 units " .

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