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muminat
3 years ago
8

Need help i don’t understand!

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0

When solving for a coefficient the variable to look for is 1

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Help please!! I will mark brainilist and give a lot of points.
julia-pushkina [17]

Answer:

a = 23.588

Step-by-step explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

8 0
2 years ago
Read 2 more answers
George and his friends rode motorcycles all day on Saturday. He made a table that showed the number of gallons of gas remaining
salantis [7]

Answer:

negative correlation

Step-by-step explanation:

his fuel keeps decreasing every time he uses his motorcycle

5 0
2 years ago
A monomial of the 2 degree with a leading coefficient of 3
Ilia_Sergeevich [38]

Answer:

In the procedure

Step-by-step explanation:

we know that

A polynomial which has only one term is called monomial

The degree of a monomial is defined as the sum of all the exponents of the variables

<em>Examples</em>

If the monomial has only one variable

3x² -----> is a monomial of the 2 degree with a leading coefficient of 3

If the monomial has more than one variable

3xy ----> is a monomial of the 2 degree with a leading coefficient of 3

6 0
3 years ago
Read 2 more answers
suppose you have a bag that hold 27 pieces of candy: 1 cream soda, 14 apple, and 12 root beer. you reach into the bag to pull ou
Alex787 [66]
I order to solve this you have to find out how how much root beer there is to the total amount of candy. 12/27. Then you find out what the percentage of root beer there is by dividing 12 by 27. It’ll give you a decimal point. Percentage has a maximum of 100%. And you’ll find out what percent based on this decimal. Factor it out of 1. The percentage you get is .44. By factoring out of 1 you can find out that the percentage is 44%. So the probability of finding a root beer out of all the candy is roughly 44%
7 0
3 years ago
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
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